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Transition metals (also called heavy metals) form insoluble compounds with hydroxide ions. Therefore, it is possible to extract heavy metal ions from water by raising the pH. The source of hydroxide ions is often a soluble metal hydroxide, such as NaOH. The complete molecular equation using NaOH to precipitate would be as follows: Са+ (аq) + 2NaоН(ад) —> Cа(ОН)2 (s) + 2Na* (aq) The cation Na+ is a spectator ion and is excluded from the net ionic equation. The balanced chemical equation can also be used to develop stoichiometric ratios. This reactions shows that 2 moles of OH are needed to precipitate each mole of Cd²+ (aq). Part D Let us assume that Cd(OH)2(s) is completely insoluble, which signifies that the precipitation reaction with NaOH(aq) (presented in the transition) would go to completion. Cd²+(aq) + 2NaOH(aq) → Cd(OH)2(s) + 2Na+ (aq) If you had a 0.550 L solution containing 0.0150 M of Cd²+ (aq), and you wished to add enough 1.30 M NaOH(aq) to precipitate all of the metal, what is the minimum amount of the NaOH(aq) solution you would need to add? Assume that the NaOH(aq) solution is the only source of OH (aq) for the precipitation. Express the volume to three significant figures and include the appropriate units. • View Available Hint(s) HÀ ? minimal volume of NAOH(aq) solution = Value Units Submit

Transition metals (also called heavy metals) form insoluble compounds with hydroxide ions. Therefore, it is possible to extract heavy metal ions from water by raising the pH. The source of hydroxide ions is often a soluble metal hydroxide, such as NaOH. The complete molecular equation using NaOH to precipitate would be as follows: Са+ (аq) + 2NaоН(ад) —> Cа(ОН)2 (s) + 2Na* (aq) The cation Na+ is a spectator ion and is excluded from the net ionic equation. The balanced chemical equation can also be used to develop stoichiometric ratios. This reactions shows that 2 moles of OH are needed to precipitate each mole of Cd²+ (aq). Part D Let us assume that Cd(OH)2(s) is completely insoluble, which signifies that the precipitation reaction with NaOH(aq) (presented in the transition) would go to completion. Cd²+(aq) + 2NaOH(aq) → Cd(OH)2(s) + 2Na+ (aq) If you had a 0.550 L solution containing 0.0150 M of Cd²+ (aq), and you wished to add enough 1.30 M NaOH(aq) to precipitate all of the metal, what is the minimum amount of the NaOH(aq) solution you would need to add? Assume that the NaOH(aq) solution is the only source of OH (aq) for the precipitation. Express the volume to three significant figures and include the appropriate units. • View Available Hint(s) HÀ ? minimal volume of NAOH(aq) solution = Value Units Submit

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Basics of Solution Stoichiometry 38 of 44 Transition metals (also called heavy metals) form insoluble compounds with hydroxide ions. Therefore, it is possible to extract heavy metal ions from water by raising the pH. The source of hydroxide ions is often a soluble metal hydroxide, such as NaOH. The complete molecular equation using ÑAOH to precipitate would be as follows: Са2+ (аq) + 2NaоН (аq) —> Са(Он)2 (s) + 2Na* (aq) The cation Nat is a spectator ion and is excluded from the net ionic equation. The balanced chemical equation can also be used to develop stoichiometric ratios. This reactions shows that 2 moles of OH are needed to precipitate each mole of Cd2+ (aq). Part D Let us assume that Cd(OH)2 (s) is completely insoluble, which signifies that the precipitation reaction with NaOH(aq) (presented in the transition) would go to completion. Cа?- (аq) + 2NaОН(аq) —» Са(Он)2 (s) + 2Na* (aq) If you had a 0.550 L solution containing 0.0150 M of Cd2+ (aq), and you wished to add enough 1.30 M NaOH(aq) to precipitate all of the metal, what is the minimum amount of the NAOH(aq) solution you would need to add? Assume that the NaOH(aq) solution is the only source of OH (aq) for the precipitation. Express the volume to three significant figures and include the appropriate units. • View Available Hint(s) HA minimal volume of NaOH(aq) solution = Value Units Submit
Transcribed Image Text:Basics of Solution Stoichiometry 38 of 44 Transition metals (also called heavy metals) form insoluble compounds with hydroxide ions. Therefore, it is possible to extract heavy metal ions from water by raising the pH. The source of hydroxide ions is often a soluble metal hydroxide, such as NaOH. The complete molecular equation using ÑAOH to precipitate would be as follows: Са2+ (аq) + 2NaоН (аq) —> Са(Он)2 (s) + 2Na* (aq) The cation Nat is a spectator ion and is excluded from the net ionic equation. The balanced chemical equation can also be used to develop stoichiometric ratios. This reactions shows that 2 moles of OH are needed to precipitate each mole of Cd2+ (aq). Part D Let us assume that Cd(OH)2 (s) is completely insoluble, which signifies that the precipitation reaction with NaOH(aq) (presented in the transition) would go to completion. Cа?- (аq) + 2NaОН(аq) —» Са(Он)2 (s) + 2Na* (aq) If you had a 0.550 L solution containing 0.0150 M of Cd2+ (aq), and you wished to add enough 1.30 M NaOH(aq) to precipitate all of the metal, what is the minimum amount of the NAOH(aq) solution you would need to add? Assume that the NaOH(aq) solution is the only source of OH (aq) for the precipitation. Express the volume to three significant figures and include the appropriate units. • View Available Hint(s) HA minimal volume of NaOH(aq) solution = Value Units Submit
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