TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT
This is the solution but I don't quite understand what it says in the writing, I need this to be made easier for me by writing it in digital format
It is a solution on the page, which is not understandable from the letter, the least they can do is accept a question credit to fix something incomplete DO NOT REJECT THE QUESTION AND LET SOMEONE DEDICATED SOLVE IT AND TAKE ADVANTAGE OF IT
![Sol" : We have to evaluate the given clouble integral
7/4
[
Sec³n dr dy
L
tanty
To evaluate the double integral first of all we have
to be change the order of integration
for which we
%= tanty
7/1/2
have to draw the bounded region
y
1
₂x = 2/₁,
지식
- 7/4
are
n=0
x=^/4
1
=> y = tank
Now take strip parallel to
y-axis
so limit of y
y = tank
y = o
limit of I are
n
0
14
1=
주
y = 0, y = 1
У=0,
x=
7/1/2
tanty
0
x
LE
dan x
AL=71/A
6
x
7
N
11
27/4
stand
7 [the fore
x=0
y=
()
1
It
y=0 x = tanly
7/4
{"S
X=0
y = 0
NA
√2
ft
1
7/4
ts
5
ť dt
-1
√2
de Ex dx dy
fe cx dy de
tank See³x du
1
TC
tanly
tank
1/4
feix dy dx
1/4
[th sucre [3]tan de
Seex [9]"
5
di
x=0
5/2
2
Peix dndy
Let & = Seck
dt Seek-tank dx
limits are t = 1
t = √√2
5
1
-
5/2_1
5
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05acc741-d43b-42c1-835f-678a6d9974b9%2F07e62923-8daf-477b-b127-8a426f6d83a1%2Fmzixtvq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Sol" : We have to evaluate the given clouble integral
7/4
[
Sec³n dr dy
L
tanty
To evaluate the double integral first of all we have
to be change the order of integration
for which we
%= tanty
7/1/2
have to draw the bounded region
y
1
₂x = 2/₁,
지식
- 7/4
are
n=0
x=^/4
1
=> y = tank
Now take strip parallel to
y-axis
so limit of y
y = tank
y = o
limit of I are
n
0
14
1=
주
y = 0, y = 1
У=0,
x=
7/1/2
tanty
0
x
LE
dan x
AL=71/A
6
x
7
N
11
27/4
stand
7 [the fore
x=0
y=
()
1
It
y=0 x = tanly
7/4
{"S
X=0
y = 0
NA
√2
ft
1
7/4
ts
5
ť dt
-1
√2
de Ex dx dy
fe cx dy de
tank See³x du
1
TC
tanly
tank
1/4
feix dy dx
1/4
[th sucre [3]tan de
Seex [9]"
5
di
x=0
5/2
2
Peix dndy
Let & = Seck
dt Seek-tank dx
limits are t = 1
t = √√2
5
1
-
5/2_1
5
2
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