Total stress at point B and also effective stress at point B OROUNDInj .AY= 1800 k$table-waterCoase lgn'redlayer2.58sat = 2200 km.B%3Dfine-grainedloyersat = 2100 kam3TTROCK8= 2500 K9m3laverSketch Not to SCALE

Given data : γ=1800 kg/m3γsat=2200 kg/m3

Answered: Total stress at point B and also…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Learning Goal: To determine the average normal strain and average shear strain in a known material based on a given load and geometry. A flat plate ABCD distorts into the dashed shape AB'C'D shown after a load is applied with a = 150.0 mm, b = 58.0 mm, g = 18.0 mm, f = 18.0 mm, and e = 8.0 mm. B 'B' b lc ; c' e D
4. What is Hooke's law? a) The relation between shear stress and the corresponding strain b) The relation between normal stress and the corresponding strain c) The relation between lateral strain and the corresponding stress d) None of the mentioned
Q-5: For the element with stresses as shown below, find: a. The magnitudes and directions of major and minor principal stresses b. The shear and normal stresses acting on a horizontal plane as shown below 8kPa 2kPa 75° 75° экра TH Jon OH 4kPa 30° Horizontal plane
Show the step by step solution for problem 2-12
Part 2,3,4
All forces applied in the system are in the (x - y) plane. The material point B at the top of the beam is rotated at an angle of 15° counterclockwise. It is required that the shear stress is 17.5 MPa for this rotated material point B. At the bottom point A of the beam it is required that the maximum tensile stress is 110 MPa. Determine the load P and the length d that satisfies these constraints defined for points A and B. Given data: L= 4 b, t = b / 25, c = 2b, b = 1000 mm, e = 12, f=5 b/4- q = 2P/L b/ 4 -b/4- P
The state of stress at a point is the result of two loadings as shown in figure. When acting alone, the first loading produces the 3 MPa pure shear with respect of xy-axis. The second loading alone results in the 4 MPa pure shear with respect to the x'y-axis. The angle between the two sets of axis is 30° as shown. If the two loadings act simultaneously then resultant (absolute) shear stress at that point with respect to x-y axis is MPa (in integer). 3 MPa st 1 loading 2 loading 4 MPa α = 30° x'
Problem 2. [Concepts: Internal forces in 2D and average normal stress] The bars of the truss each have a cross-sectional area of 1.25 in². a) Determine the average normal stress in each member due to the loading P = 8 kip. State whether the stress is tensile or compressive. b) If the maximum average normal stress in any bar is not to exceed 20 ksi, determine the maximum magnitude P of the loads that can be applied to the truss. 4 ft 4 ft 4 E 0.75 P 0
A 180-mm length of 30 x 40 mm solid rectangular bar is loaded as shown in the diagram. The right end of the tube is fixed to a rigid frame while the left end is free. (a) Draw the stress element for point B at the top center of the bar (right end) and label the stress vectors acting on the element, including the stress magnitudes. (b) Draw the stress element for point C at the middle of the front face of the bar (right end) and label the stress vectors acting on the element, including stress magnitudes
1. The stress condition on a two-dimensional infinitesimal material element is shown in Fig. 1 Fig. 1 60 MPа A 50 MPа В 30 MPа A. Describe the state of stress on: (i) Face A (ii) Face B B. State the sign convention for stress components on faces A and B in the: (i) Physical-space (ii) Mohr-Circle-space C. Draw the Mohr circle for the stress element in Fig. 1
If the block is subjected to the centrally applied force of 600kN, determine the average normal stress in the material. Show the stress acting on a differential volume element of the material
a) 0.040 m b) 0.260 m c) 0.020 m d) 0.300 m

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