Tolerance 132: ±1 in the 4th Sig Fig Hide Information Calculation 132: The tolerance for this calculation is 4 Sig Figs. Your answer, 0.948, contains 3 Sig Figs. Your answer has not been evaluated for correctness, only for Sig Figs; also, no points have been deducted. Please make the necessary change and click the Submit button.

Tolerance 132: ±1 in the 4th Sig Fig Hide Information Calculation 132: The tolerance for this calculation is 4 Sig Figs. Your answer, 0.948, contains 3 Sig Figs. Your answer has not been evaluated for correctness, only for Sig Figs; also, no points have been deducted. Please make the necessary change and click the Submit button.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Application 14. Given the function f(x) = 3x3 - 48x find the following: (Round to 1 decimal place) a) The x and y intercepts [K/U: ] b) The local maximums and minimums [A:. c) Find any points of inflections [A: I d) Graph the function [C 5
9) The following results were obtained in the determination of Vitamin E mass in tablet samples. Sample 1 2 3 4 5 6 Weight of Vitamin E (mg) 249.1 249.9 251.2 250.2 244.8 251.0 i. Determine whether any data should be rejected or not at 90 % confidence level. ii. Calculate the mean and standard deviation of the data set above. ii. Express the mean weight of vitamin C at 99 % confidence interval.
QUESTION 16 Match the correct choices with the given. For gravimetric analysis, use this data to answer the questions. |Trial 1 0.6020 g 24.8405 g 24.8451 g 24.8422 Trial 2 0.5021 g 22.8165 g 22.8165 g Trial 3 0.5018 g 22.8169 g 22.8169 g |Weight of Sample Weight of Crucible and Ba$O, 8 24.8422 g Constant Weight of Crucible & Sample 24.8422 g 22.8165 g 22.8169 g Weight of Crucible 24.3181 22.3593 g 22.3641 g 24.3160 g 24.3142 g 24.3142 g 24.3142 g 24.3142 g 22.3523 g 22.3534 g 22.3532 g 22.3532 g 22.3612 g 22.3605 g 22.3605 g 22.3605 g Constant Weight of Crucible 22.3532 g 22.3605 g Weight of BaSo, |% so,2- Average Standard deviation Relative standard deviation A. 2.65 Average of the % (w/w) SO42- B. to decompose the solid and form a compound of known composition and to remove the solvent and any non-volatile species Standard deviation of the % (w/w) So2- Relative standard deviation of the C. reprecipitation % (w/w) SO42- D. formation of small crystals This is a drastic but effective…
Multiply sig figs
esc mb V ps lock Ft ! 1 control 141 PI Q >> A @ 2 * F2 28. NR # 80 F3 $ 888 FA % 20 FO A 244 FO & 44 F7 Aa * D'Il FB Some matches consist of a wooden stick and a head that contains tetraphosphorous trisulfide, P4S3(s), and that can be ignited on any rough surface. When the match is drawn across a rough surface, enough heat is generated to start the reaction represented by the following equation. and pur The energy that is transferred when 69.1 g of XeF4(s) is produced is DD FO Use the following information to answer the next question. Xenon tetrafluoride is a binary compound made from a noble gas. The formation of xenon tetrafluoride can be represented by the following equation. Xe(g) + 2 F₂(g) → XeF4(s) AH=-251 kJ Use the following information to answer the next two questions. DIDIOMBATILAI P4S3(s) + 8 O₂(g) → SO₂(g) A,HP,S, (S) A,HO P.O₁0(s) J F10 kJ. P4010(s) + 3 = -155.0 kJ/mol = -2 984.0 kJ/mol TULBUR di F11 F12 IN G elete 1 urn ift
a Wagne, MINTEG CHEMPHYS X Playng a Game Que i quizizz comy pn/game/U2FsdGVIX1252FEzKAPoy252FXxFqQZNEN252FGHBITgOU252B2XYinpkgiq17227p04252FNDA 4Xmes0DBS1252BO123252BpaKFgo 8 63rd E 600 4/55 The mass number of an element that has 5 protons, 5 electrons, and 6 neutrons is 11 10 16 backspace
Time(s) [X3] (mole/L) 0 0.600 500 0.481 1000 0.392 1500 0.336 2000 0.273 2500 0.230 3000 0.181 3500 0.156 4000 0.120 4500 0.106 5000 0.072 plot ln[X3] vs time plot 1/[X3] vs. time
Cl₂(g) + 2e Cr₂0 (aq) + 14 H(aq) + 6e¯ 02(g) +4H(aq) + 4e¯ MnO2(s) + 4H(aq) + 2e 103 (aq) +6H(aq) + 5e¯ VO₂ (aq) + 2H(aq) + e¯ Br₂() + 2e NO, (aq) + 4H(aq) + 3e¯ ClO2(g) + e Ag+(aq) + e 2 CT (aq) 1.36 2 Cr3+(aq) + 7 H₂O(1) 1.33 2 H₂O(1) 1.23 Mn2+(aq) + 2 H2O() 1.21 12(aq) + 3H2O(l) VO2+(aq) + H2O(l) 1.20 1.00 2 Br (aq) 1.09 NO(s) + 2 H2O(l) CIO₂(aq) 0.96 0.95 Ag(s) 0.80 0.77 Fe3+(aq) + e Fe2+(aq) A mixture of Fe3+, CIO₂, and Cr₂O,² was made, what reaction would be predicted, if any? a. Fe3+ + Cr2O7²- b. Cr2O + Clo²- c. Fe3+ Clo²- d. No reaction. -> -> Fe²+ + Cr³+. - Cr3+ + ClO2. Fe²+ + ClO2.
Name: Part I: Calibration of the Plastic Pipette Number of Drops Total Mass (g) Mass of 10 Drops (g) Volume of 10 Drops (mL) 23.3124 10 23.8216 20 24.2999 30 24.8245 1. Temperature of deionized water (°C) 24.7 2. Density of water at this temperature from (g/mL) Density calculator https://antoine.frostburg.edu/chem/senese/javascript/water-density.html 3. Average volume of 10 drops (mL) show calculation: Part II: Determination of Standard Solutions mL of 0.200M CuSO4'5 H20 added M CuSO4 diluted Absorbance Tube # mL H20 added 0.200 1.346 about 3 0.945 3 4.00 1.00 0.715 4 3.00 2.00 0.469 2.00 3.00 0.281 6. 1.00 4.00 show calculation for Tube #3 diluted concentration:
All changes save 7. When two solutions are mixed, a color change occurs. The data tables show the time between mixing and the color change for two sets of conditions. For Condition One, the solution concentrations were constant and temperature varied. For Condition Two, the temperature was constant and concentrations varied. Condition One: Concentration Time for Temperature (°C) Sample Color to Change 1 10° 36 sec 22° 14 sec Condition Two: Temperature Time for Concentration Sample Color to % Change 1. 100% 15 sec 2. 50% 24 sec Which of these statements is true according to the data? O The reaction rate is greater at 22°C than at 10°C. O Reducing the temperature increases the rate of the reaction. The reaction is affected by changes in temperature not by changes in concentration. O Decreasing the concentration increases the reaction rate. PREVIOUS 17 of 25 NEXT SAVE & EXIT
The following volumes of 0.000300 M SCN are diluted to 15.00 mL. Determine the concentration of SCN in each sample after dilution. These values will be used during the experiment. To enter exponential values, use the format 1.0e-5. Sample 0.000300 M SCN (mL) [SCN'] (M) 1 1.50 3.50 7.00 4 10.00 3.
2 3 4 -5 g . Use this information to calculate K.n for PbCO2. The solubility of PbCO, in water at 25 °C is measured to be 7.3 × 10 sp Round your answer to 2 significant digits. Continue O 2022 McGraw Hill LLC. All Rights Reserved. Ter II 20