tocation alonyHhe beam length,At maximum bendingfiad the ben ding streas at point B.3 cm30N13N/m2 N.mo5m1-5 m+"t Lo.z com

Answered: tocution aloy the beam length, bending…

tocution aloy the beam length, bending find the bending otreas at poin t B. 13N/M At maximum tocation 3 cm 30N 2 N.m |osm, 1.5m O-5m 1-5 m , Im 0.5cm k

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Fi-9 II the heam ts suhjecied to a bending moment of M= 20 EN-m delemine the mimum bending siress in the beam. 20
/Acantilever beam of length 4m cauries point Loads of 1 KN ,2KN and 3KN at 1,2 and am from the fixedend, oraw the Shear force and B.M. diaqrams for the cantilever ? quicky Please I need answer
Use any of the 3 method of beam deflection find the location and maximum vertical displacement it can produce.
O K Question 1 The differential equation; M = - El d2y/dx² provides the means by which the deflections of beams can be determined. The product of El is known as, (A) the Flexural Rigidity of a beam B none of the above. the Section Modulus of a beam the Second Moment of Inertia of a beam
e following:- Answer two questions of 01: Choose the correct answer from the following:- 1. The relationship between maximum shear stress and average shear stress for a rectangular section is given as: a) Tavg. = 1.33tmay. 2. The bending stress of I – section beam is maximum at: a) neutral axis. b) Tmax. = 1.337,vg. c) Tavg. = 0.666Tmay. d) Tmax. = 1.5Tavg. b) top layer. c) bottom layer. d) top and bottom layers. 3. The extremities of any diameter on Mohr's circle represent: a) principal stresses. d) none of the above. 4. A body is subjected to a two normal stresses 20MPA (tensile) and 10MPA (compressive), acting perpendicular to each other. The maximum shear stress is: b) normal stress on plane at 45°. c) shear stress on plane 45°. а) 5MPa. b) 10MPа. с) 30MPа. d) 15MPA. 5. A mild steel shaft is subjected to a bending moment M = 400N.m and torque T = 300N.m . The equivalent bending moment is: a) 900N.m b) 700N.m c) 500N.m d) 450N.m
Problem 7.65 - Enhanced - with Hints and Feedback Figure 3 m 6 m 12 kN/m 4 of 15 ■Review Draw the moment diagram for the beam. Follow the sign convention. Click on "add vertical line off" to add discontinuity lines. Then click on "add segment" button to add functions between the lines. Note 1 - Draw a vertical line to denote local maximum or minimum. Note 2 - The curve you choose from the drop-down is only a pictorial representation of a real quadratic/cubic curve. The equation of this curve is not mathematically equivalent to the correct answer. Consequently, slopes at discontinuities and intercepts with the x-axis (if any) are not accurate. 1 of 1 ▸ View Available Hint(s) B الا 十四 A i ✓ ? 3 m 12 kN/m с 6 m M (kN·m) No elements selected 50 40- B 10:04 PM
Question
What is the maximum bending moment in the beam in kNm? the absolute magnitude of the moment must be taken into account
HW #3 04/12/2020 due date. wednesden Tx=/25 MPa T2=? uncler Novolume cheye! do 10cm 20=0 ( For novalmachaye Sscm Socm N: 0.4 E= 10 k 125-10040z=0 102= -25 MPa Fz=? Az 0.2m X0.3m %3D Q: Ex=? final dianeter. F2 -25M x (200 mx 300) t2= -1500000N~/500KN
do it neat and clean kindly
i need the answer quickly