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We found our shear force and bending moment through section cut method, now we need shear forces and moment diagrams of each beam. Beam 1 Ay By: rcoction force = 8212,4N Ayoroction farce = - 1231N → Final support ma bendling monent =-2035,7 Nm 1100 mM E 2kN V: Shuar force - - 4176,9 N We,: Weight of Hee beam 2945,9 External pin Support "By Beam 2

We found our shear force and bending moment through section cut method, now we need shear forces and moment diagrams of each beam. Beam 1 Ay By: rcoction force = 8212,4N Ayoroction farce = - 1231N → Final support ma bendling monent =-2035,7 Nm 1100 mM E 2kN V: Shuar force - - 4176,9 N We,: Weight of Hee beam 2945,9 External pin Support "By Beam 2

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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We found our shear force and bending moment through section cut method, now we need shear forces and moment diagrams of each beam. Ay Beam 1 By: rcoction foree = 8212,4N Aysrooction force =: - 1231N → Fineal support g bendling moment >-2035,7 Nom Ay 1100 mM E 2k N 4176,9N 550nn By External pin support V4: Shar force We,: Weight of He beam 2945,9N Beam 2 1000mn By: : rsoc tiàn forcee 8212,4N WB2: weight of the beom 2 =2206,3 N 2955,7 N m By V2: Shear fons = GOO6,A N fized Support %3D Wi Weight of the lead = 981 N Wc: Weight of the head part= 868,2
Transcribed Image Text:We found our shear force and bending moment through section cut method, now we need shear forces and moment diagrams of each beam. Ay Beam 1 By: rcoction foree = 8212,4N Aysrooction force =: - 1231N → Fineal support g bendling moment >-2035,7 Nom Ay 1100 mM E 2k N 4176,9N 550nn By External pin support V4: Shar force We,: Weight of He beam 2945,9N Beam 2 1000mn By: : rsoc tiàn forcee 8212,4N WB2: weight of the beom 2 =2206,3 N 2955,7 N m By V2: Shear fons = GOO6,A N fized Support %3D Wi Weight of the lead = 981 N Wc: Weight of the head part= 868,2
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