To whom it may concern, I was trying to complete some problems with mole conversions from the book "General Chemistry: Principles and Modern Applications Eleventh Edition" when I ran into trouble. The question, which is Chapter 3 Exercise #11 in the book, is written as follows: "Determine the number of moles of: (b.) N atoms in a sample of Mg(NO3)2 (c.) N atoms in a sample of C7H5(NO2)3 that has the same number of O atoms as 12.4g C6H12O6. While I understand the process of getting to the # of moles in each sample and then converting to the individual atom's moles, I'm confused as to why the answer doesn't then also use avagdro's number to find the exact amount of atoms. For reference the answers for part b and c as shown in its appendix are 0.587 mol N atoms and 0.206 mol N atoms respectively. If you could explain the process of doing this problem and why it stops where it does, It would help immensely. Thanks, Daniel Marino
To whom it may concern,
I was trying to complete some problems with mole conversions from the book "General Chemistry: Principles and Modern Applications Eleventh Edition" when I ran into trouble. The question, which is Chapter 3 Exercise #11 in the book, is written as follows: "Determine the number of moles of: (b.) N atoms in a sample of Mg(NO3)2 (c.) N atoms in a sample of C7H5(NO2)3 that has the same number of O atoms as 12.4g C6H12O6. While I understand the process of getting to the # of moles in each sample and then converting to the individual atom's moles, I'm confused as to why the answer doesn't then also use avagdro's number to find the exact amount of atoms. For reference the answers for part b and c as shown in its appendix are 0.587 mol N atoms and 0.206 mol N atoms respectively. If you could explain the process of doing this problem and why it stops where it does, It would help immensely.
Thanks,
Daniel Marino
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