3. Aluminum sulfite reacts with sodium hydroxide to form sodium sulfite and aluminum hydroxide according to the following equation. Al,(SO.), + 6 NaOH ------> 3 Na,So, + 2 Al(OH), a) Determine the limiting reactant if 20.0 g of Al,(SO,), reacts with 20.0 g of NaOH. b) Determine the number of moles and mass of Al(OH), produced. c) Determine the number of moles and mass of Na SO, produced.

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3.C) Determine the number of moles and mass of Na2SO3 produced. 

Al2(SO3)3 + 6NaOH -> 3Na2SO3 + 2Al(OH)3

3. Aluminum sulfite reacts with sodium hydroxide to form
sodium sulfite and aluminum hydroxide according to
the following equation.
Al,(SO.), + 6 NaOH ------> 3 Na,So, + 2 Al(OH),
a) Determine the limiting reactant if 20.0 g of Al,(SO,),
reacts with 20.0 g of NaOH.
b) Determine the number of moles and mass of
Al(OH), produced.
c) Determine the number of moles and mass of
Na SO, produced.
Transcribed Image Text:3. Aluminum sulfite reacts with sodium hydroxide to form sodium sulfite and aluminum hydroxide according to the following equation. Al,(SO.), + 6 NaOH ------> 3 Na,So, + 2 Al(OH), a) Determine the limiting reactant if 20.0 g of Al,(SO,), reacts with 20.0 g of NaOH. b) Determine the number of moles and mass of Al(OH), produced. c) Determine the number of moles and mass of Na SO, produced.
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