To what volume shauld I lomL of a 6,7M HCl salution be dilu ted t prepare a O.30M HCl Solution?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter4: Types Of Chemical Reactions And Solution Stoichiometry
Section: Chapter Questions
Problem 7ALQ: Consider separate aqueous solutions of HCl and H2SO4 with the same molar concentrations. You wish to...
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**Question:**

To what volume should 16 mL of a 6.7 M HCl solution be diluted to prepare a 0.30 M HCl solution?

**Explanation:**

This exercise asks for the final volume required to dilute a concentrated hydrochloric acid (HCl) solution. It involves using the concept of dilution in chemistry.

**Formula for Dilution:**

\[ C_1V_1 = C_2V_2 \]

Where:

- \( C_1 \) is the initial concentration (6.7 M HCl),
- \( V_1 \) is the initial volume (16 mL),
- \( C_2 \) is the final concentration (0.30 M HCl),
- \( V_2 \) is the final volume (unknown).

Using this formula, you can solve for \( V_2 \):

\[ (6.7\, \text{M}) \times (16\, \text{mL}) = (0.30\, \text{M}) \times V_2 \]

From this equation, rearrange to solve for \( V_2 \):

\[ V_2 = \frac{6.7\, \text{M} \times 16\, \text{mL}}{0.30\, \text{M}} \]

Calculate the result:

\[ V_2 = \frac{107.2\, \text{mL} \cdot \text{M}}{0.30\, \text{M}} \]

\[ V_2 = 357.33\, \text{mL} \]

Therefore, the 16 mL of a 6.7 M HCl solution should be diluted to 357.33 mL to prepare a 0.30 M HCl solution.
Transcribed Image Text:**Question:** To what volume should 16 mL of a 6.7 M HCl solution be diluted to prepare a 0.30 M HCl solution? **Explanation:** This exercise asks for the final volume required to dilute a concentrated hydrochloric acid (HCl) solution. It involves using the concept of dilution in chemistry. **Formula for Dilution:** \[ C_1V_1 = C_2V_2 \] Where: - \( C_1 \) is the initial concentration (6.7 M HCl), - \( V_1 \) is the initial volume (16 mL), - \( C_2 \) is the final concentration (0.30 M HCl), - \( V_2 \) is the final volume (unknown). Using this formula, you can solve for \( V_2 \): \[ (6.7\, \text{M}) \times (16\, \text{mL}) = (0.30\, \text{M}) \times V_2 \] From this equation, rearrange to solve for \( V_2 \): \[ V_2 = \frac{6.7\, \text{M} \times 16\, \text{mL}}{0.30\, \text{M}} \] Calculate the result: \[ V_2 = \frac{107.2\, \text{mL} \cdot \text{M}}{0.30\, \text{M}} \] \[ V_2 = 357.33\, \text{mL} \] Therefore, the 16 mL of a 6.7 M HCl solution should be diluted to 357.33 mL to prepare a 0.30 M HCl solution.
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