To solve for the moment and reactions of the beam shown, the three-moment equation is useful. The three moment equation is given as: 6Aa MA(L,) + 2Mg(L1+L2) + MdL) + 6Ab - 0: Assuming that there is no settlement of supports and El is constant for the whole structure. L2 L1 6Aa 6A5 L1 is called the "Factors" of the three-moment equation which can be determined by using the Moment-Area diagram of the left span and right span of the beam and also by using integral calculus. L2 For the loading shown below, determine the value of the resulting "Factors" when W1 = W2 = 15 kN/m, a = 2 meters, b = 3 meters. ROUND OFF TO TWO DECIMAL PLACES. W1 W2 В a a a b

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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The given values provided below is For the loading shown below, determine the value of the resulting "Factors" when W1 = W2 = 16 kN/m, a = 2 meters, b = 2 meters.

 

Mine is For the loading shown below, determine the value of the resulting "Factors" when W1 = W2 = 15 kN/m, a = 2 meters, b = 3 meters.

 

 

To solve for the moment and reactions of the beam shown, the three-moment equation is useful. The three moment equation is given as:
6Aa
6Ab
- 0: Assuming that there is no settlement of supports and El is constant for the whole structure.
MA(L1) + 2Mg(L1+ L2 + MCL2) +
+
L1
L2
6Aā
6Ab
is called the "Factors" of the three-moment equation which can be determined by using the Moment-Area diagram of the left span and right span of the beam and also by using integral calculus.
+
L1
L2
For the loading shown below, determine the value of the resulting "Factors" when W1 = W, = 15 kN/m, a = 2 meters, b = 3 meters.
ROUND OFF TO TWO DECIMAL PLACESs.
W1
W2
a
a
a
b
b
b
Transcribed Image Text:To solve for the moment and reactions of the beam shown, the three-moment equation is useful. The three moment equation is given as: 6Aa 6Ab - 0: Assuming that there is no settlement of supports and El is constant for the whole structure. MA(L1) + 2Mg(L1+ L2 + MCL2) + + L1 L2 6Aā 6Ab is called the "Factors" of the three-moment equation which can be determined by using the Moment-Area diagram of the left span and right span of the beam and also by using integral calculus. + L1 L2 For the loading shown below, determine the value of the resulting "Factors" when W1 = W, = 15 kN/m, a = 2 meters, b = 3 meters. ROUND OFF TO TWO DECIMAL PLACESs. W1 W2 a a a b b b
ll TM ?
12:24 PM
33%
Answer 1 of 1
Done
The solution for your question is given below.
Please check it out and ask if any doubts. Please
do rate it and thanks.
Civen.
wz =16 kN/m
A
to
2m
Three Momeut equation.
MA CL) + 2mB (4sthe)+Mc(kz)+ GAä
GAE
Hene a = from lett
= trom vight
6Aa
6Ab
ane faitors
Nowe
Pa(a+)
16 kN)m
LI
Hene
P= Ydx
And
a =
X+2
pzydx
2
y = x =2)
16
2
%3D
: 6A ā
dz
2
(st 162)(31-x²-4 +ux) dx
%3D
2
( (288x-8x-32x+32x+576x-16x3
11
- 64x + 64x²) da
s (320x-
512x) dx
2.
6A ā
314.22
し)
ly
on span BC loading is Same
.: 6 Ab
314.22
%3D
please
don't forget to rate it and thanks.
Transcribed Image Text:ll TM ? 12:24 PM 33% Answer 1 of 1 Done The solution for your question is given below. Please check it out and ask if any doubts. Please do rate it and thanks. Civen. wz =16 kN/m A to 2m Three Momeut equation. MA CL) + 2mB (4sthe)+Mc(kz)+ GAä GAE Hene a = from lett = trom vight 6Aa 6Ab ane faitors Nowe Pa(a+) 16 kN)m LI Hene P= Ydx And a = X+2 pzydx 2 y = x =2) 16 2 %3D : 6A ā dz 2 (st 162)(31-x²-4 +ux) dx %3D 2 ( (288x-8x-32x+32x+576x-16x3 11 - 64x + 64x²) da s (320x- 512x) dx 2. 6A ā 314.22 し) ly on span BC loading is Same .: 6 Ab 314.22 %3D please don't forget to rate it and thanks.
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