To make gold (Au) stronger and harder, it is often alloyed with other metals, such as copper (Cu) and silver (Ag). Consider two alloys, one of Au and Cu and one of Au and Ag, each with the same mole fraction of Au. If the Au/Cu alloy is harder than the Au/Ag alloy, what could be the best explanation based on the information in the table?| Element | Metallic Radius (pm) | Melting Point (°C) | Common Oxidation State ||---------|----------------------|-------------------|------------------------|| Au | 144 | 1064 | 1+, 3+ || Cu | 128 | 1085 | 1+, 2+ || Ag | 144 | 961 | 1+ |**Explanation of Table:**- **Element Column:** Lists the elements being considered in the alloys.- **Metallic Radius (pm):** Shows the size of the atoms in picometers. Au and Ag share the same metallic radius of 144 pm, while Cu has a smaller radius of 128 pm.- **Melting Point (°C):** Indicates the temperature at which each metal melts. Cu has the highest melting point at 1085°C, followed by Au at 1064°C, and Ag at 961°C.- **Common Oxidation State:** Lists the typical oxidation states of the elements, with Au having the most variable states (1+, 3+).*Inference:* The Au/Cu alloy may be harder due to the smaller metallic radius of Cu, which can enhance the atomic packing efficiency and the strength of the alloy. Additionally, Cu's higher melting point could contribute to increased hardness compared to Ag.

Size of Cu (128 pm) is smaller than Ag(144 pm). This size difference makes Au/Cu alloy is harder than Au/Ag alloy.

To make Au stronger and harder, it is often alloyed with other metals, such as Cu and Ag. Consider two alloys, one of Au and Cu and one of Au and Ag, each with the same mole fraction of Au. If the Au/Cu alloy is harder Au than the Au/Ag alloy, what could be the best explanation based on the information in the table? Element Metallic Melting Common oalo Radius Oxidation State Point (pm) 144 (°C) 1064 1+, 3+ 1+, 2+ Cu 128 1085 Ag 144 961 1+ elo sonslev ali on

To make Au stronger and harder, it is often alloyed with other metals, such as Cu and Ag. Consider two alloys, one of Au and Cu and one of Au and Ag, each with the same mole fraction of Au. If the Au/Cu alloy is harder Au than the Au/Ag alloy, what could be the best explanation based on the information in the table? Element Metallic Melting Common oalo Radius Oxidation State Point (pm) 144 (°C) 1064 1+, 3+ 1+, 2+ Cu 128 1085 Ag 144 961 1+ elo sonslev ali on

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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