to HBr

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ONLY USE THINGS LEARNED IN ORGANIC CHEM 1

Show stepwise mechanism by pushing arrows (Fishhook) and drawing all intermediates:  Draw a detailed mechanism for the addition of HBr to 3,3-dimethyl-1-butene in the presence of dimethylperoxide. Show and label all steps including initiation, propagation and termination.   

 

**Alkene Hydrohalogenation Reaction**

In the provided image, we can observe an example of an electrophilic addition reaction, specifically the hydrohalogenation of an alkene.

**Chemical Equation:**

\[ \mathrm{CH_2=CH-CH_3 + HBr \rightarrow CH_3-CH(Br)-CH_3} \]

- **Starting Material:** The left side of the image showcases an alkene with the molecular formula \(\mathrm{CH_2=CH-CH_3}\). Alkenes are hydrocarbons that feature a carbon-carbon double bond.

- **Reagent:** An \( \mathrm{HBr} \) molecule is shown as the reagent. Hydrohalogenation involves the addition of a hydrogen halide (in this case, hydrogen bromide) to an alkene, resulting in the formation of a haloalkane (alkyl halide).

- **Mechanism and Product:** The reaction proceeds with the double bond being broken and an addition of hydrogen and bromine atoms across the former double bond. The product formed is shown on the right side of the arrow. The final product is a bromoalkane where the bromine atom is added to the carbon with the greater number of hydrogen atoms (Markovnikov's rule).

This transformation converts an alkene into a more reactive alkyl halide compound.
Transcribed Image Text:**Alkene Hydrohalogenation Reaction** In the provided image, we can observe an example of an electrophilic addition reaction, specifically the hydrohalogenation of an alkene. **Chemical Equation:** \[ \mathrm{CH_2=CH-CH_3 + HBr \rightarrow CH_3-CH(Br)-CH_3} \] - **Starting Material:** The left side of the image showcases an alkene with the molecular formula \(\mathrm{CH_2=CH-CH_3}\). Alkenes are hydrocarbons that feature a carbon-carbon double bond. - **Reagent:** An \( \mathrm{HBr} \) molecule is shown as the reagent. Hydrohalogenation involves the addition of a hydrogen halide (in this case, hydrogen bromide) to an alkene, resulting in the formation of a haloalkane (alkyl halide). - **Mechanism and Product:** The reaction proceeds with the double bond being broken and an addition of hydrogen and bromine atoms across the former double bond. The product formed is shown on the right side of the arrow. The final product is a bromoalkane where the bromine atom is added to the carbon with the greater number of hydrogen atoms (Markovnikov's rule). This transformation converts an alkene into a more reactive alkyl halide compound.
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