To find the percentage of Na2CO3 in the (NaCl + Na2CO3) mixture in a laboratory experimentneutralization titration was performed. For this purpose, 0.15 g dissolved in distilled water4-5 drops of methyl-orange indicator were added into the mixture and then titrated with HCl.were. The data obtained are given below. According to these data, the percentage of Na2CO3 in themixtureCalculate (Na: 23, C: 12, 0: 16, Cl: 35.5 g/ mol).co,²+HHCO;HCO;+HH,CO;H;CO3Н-О + СОCo?²+ 2H° -Н.О + СО• The concentration of HCl solution used in titration: MHCI = 0.08 mol / L• Consumption amount of HCl solution: VHCI = 13.5 mL

Introduction: The reaction of sodium carbonate with hydrochloride acid has proceeded as given below.…

To find the percentage of Na2CO3 in the (Nacl + Na2CO3) mixture in a laboratory experiment neutralization titration was performed. For this purpose, 0.15 g dissolved in distilled water 4-5 drops of methyl-orange indicator were added into the mixture and then titrated with HCI. were. The data obtained are given below. According to these data, the percentage of Na2CO3 in the mixture Calculate (Na: 23, C: 12, 0: 16, Cl: 35.5 g / mol). HCO; HCO;+H- H,CO; H;CO; > H;O + CO2 co,*+ 2H°• H2O + CO2 The concentration of HCl solution used in titration: MHCI = 0.08 mol / L • Consumption amount of HCl solution: VHCI = 13.5 ml

To find the percentage of Na2CO3 in the (Nacl + Na2CO3) mixture in a laboratory experiment neutralization titration was performed. For this purpose, 0.15 g dissolved in distilled water 4-5 drops of methyl-orange indicator were added into the mixture and then titrated with HCI. were. The data obtained are given below. According to these data, the percentage of Na2CO3 in the mixture Calculate (Na: 23, C: 12, 0: 16, Cl: 35.5 g / mol). HCO; HCO;+H- H,CO; H;CO; > H;O + CO2 co,*+ 2H°• H2O + CO2 The concentration of HCl solution used in titration: MHCI = 0.08 mol / L • Consumption amount of HCl solution: VHCI = 13.5 ml

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: 16. Perform all of the following calculations. a) To simulate blood conditions, a phosphate buffer…

A: The phosphate buffer system consists of two components Na2HPO4 and NaH2PO4. The dissociations of…

Q: What would be the pH values when (a) 0.0090 mol HCI and (b) 0.0090 mol NaOH, added to 0.300 L of a…

A: Given(a): Concentration of HCl = 0.0090 Mb): Concentration of NaOH = 0.0090 MConcentration of Volume…

Q: Use the ‘oxidation number method’ and balance the unfinished, ionic equation below.…

A: Answer

Q: A 0.2386-g sample contained only NaCl and KBr was dissolved in water and required 50.00 mL of…

A: The mathematical relationship between the number of moles and the mass of the substance can be…

Q: The student Louise continued the analysis of acetic acid using half - neutralization technique. She…

A: The reaction between acetic acid and NaOH is NaOH + CH3COOH --------> CH3COONa + H2O

Q: A mixture of HCl and H3PO4 is titrated with 0.100 M NaOH. The first end point (methyl red) occurs at…

A: The objective of the question is to calculate the millimoles and present in the solution.

Q: you want to separate Ni2+ and Mn2+ by precipitating the corresponding sulphides from each other.…

A: Given dataKsp (NiS): 10-21,Ksp (MnS): 10-15,Ksp (H2S): 10- 20 ,Saturation concentration of H2S in…

Q: Part b and C What volume of 0.110 M HCI is required for the complete neutralization of 1.10 g of Na2…

A: From the balanced chemical reaction between HCl and Na2CO3, we can solve these problems. 2HCl +…

Q: You will perform several calculations with the data you obtain in the titrations lab. Below is an…

A: Molarity is defined as the number of moles of solute divided by volume of solution in litres. By…

Q: What is the Molar Mass (g/mol) of an unknown monoprotic weak acid if 648 mg of it requires 35.86 mL…

Q: The chemical 5-amino-2,3-dihydro-1,4-phthalazinedione, better known as luminol, is used by forensic…

A: Molarity of a solution represents the concentration of a solute in the solution, which is expressed…

Q: A solution is made with 554 ml of 8.21 M HX solution and 549 mL of 6.06 M Nax solution and the pH at…

Q: A sample is known is known to consist of NaOH (40 g/mol) or NaHCO3 (84 g/mol), or Na2CO3 (106 g/mol)…

A: Given that : The sample contains : NaOH (40 g/mol) or NaHCO3 (84 g/mol), or Na2CO3 (106 g/mol) or…

Q: 1). The sample of 25.00 mL of 0.010 M HCOOH is titrated with 0.020 M KOH. (a) Show the reaction…

A: Since you have asked question with multiple subpart, we will solve the first three subpart question…

Q: d. Oxalic acid (H2C2O4) is the compound that gives rhubarb its tart flavor, and it is also a toxin…

A: The question is based on the concept of molarity.Molarity is a method of expressing concentration of…

Q: 0.4201 g of a unknown monoprotic acid was dissolved in 25.00 mL of water and titrated with 0.09995 M…

Q: The pK, value for HCIO is 7.46. Would a buffer prepared from HCIO and NaClO with a pH of 5.66 be…

Q: An analytical chemist Is titrating 108.4 mL of a 0.2200M solution of plperidine (CH10 NH) with a…

Q: I prepare a buffer solution by mixing 30.0mL of 0.10M HOAc and 40.0mL of 0.10m NaOAc. I divide this…

Q: What is the pH at the equivalence point in the titration of 0.50 M KOH with 1.00 L of 0.750 M HF(aq)…

A: 1- First calculate the volume of KOH : We will used the equation, ( M2V2)KOH = ( M1V1)HF ( 0.50M ×…

Q: For the determination of basic species in 0.1878 g Talcid sample; 20 mL of 0.1009 M HCl solution was…

A: The % base amount in CaCO3 is to be determined from the given data. Given: Mass of sample = 0.1878 g…

Q: 25.0 ml of 0.100M NaOH is titrated with HC2H3O2 and 50.0mL of the acid is used to reach the…

A: FORMULA USED M1V1(NaOH) = M2V2(HC2H3O2)

Q: A 20.00-ml sample contains 1.00 g of NAHCO,. This sample is used to standardize an NAOH solution. At…

A: Given : Mass of NaHCO3 = 1.00 g Volume of NaHCO3 solution = 20.00 mL = 0.020 L…

Q: A 8.06 g sample of benzoic acid was dissolved in water to give 60.6 mL of solution. This solution…

A: Mass of benzoic acid = 8.06 gVolume of solution = 60.6 mLConverting to liters:Molarity of NaOH =…

Question

To find the percentage of Na2CO3 in the (NaCl + Na2CO3) mixture in a laboratory experiment
neutralization titration was performed. For this purpose, 0.15 g dissolved in distilled water
4-5 drops of methyl-orange indicator were added into the mixture and then titrated with HCl.
were. The data obtained are given below. According to these data, the percentage of Na2CO3 in the
mixture
Calculate (Na: 23, C: 12, 0: 16, Cl: 35.5 g/ mol).
co,²+H
HCO;
HCO;+H
H,CO;
H;CO3
Н-О + СО
Co?²+ 2H° -
Н.О + СО
• The concentration of HCl solution used in titration: MHCI = 0.08 mol / L
• Consumption amount of HCl solution: VHCI = 13.5 mL

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Calculation:

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

5:51 1 .ll LTE Search Question 16 of 20 Submit Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH, with 0.100 M HNO3 after 80.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6. 1 2 4 Based on the result of the acid-base reaction, set up the unknown. ICE table in order to determine the H2NNH3*(at H2O(1) =H;O*(aq) H2NNH2(aq + Initial (M) Change (M) Equilibrium (M) RESET 0.100 0.200 0.0333 0.0667 +x -X 0.100 + x 0.100 - x 0.200 + x 0.200 - x 0.0333 + x 0.0333 - x 0.0667 + x 0.0667 - x www
Determine the pH during the titration of 62.0 mL of 0.342 M formic acid (K,- 1.8x104) by 0.342 M KOH at the following points. (Assume the titration is done at 25 °C.) (a) Before the addition of any KOH (b) After the addition of 15.0 mL of KOH (c) At the half-equivalence point (the titration midpoint) (d) At the equivalence point (e) After the addition of 93.0 mL of KOH
1) Please don't provide handwrittren solution...
1). The sample of 25.00 mL of 0.010 M HCOOH is titrated with 0.020 M KOH. (please answer part D only). (a) Show the reaction between HCOOH and OH–. (b) Find the volume of 0.020 M KOH needed to reach the equivalence point. (c) Show the reaction of hydrolysis of product from the step (a). (d) Calculate the pH at the equivalence point (Kb of HCOO– is 5.6 x 10–11)
0.2 mL of 0.10M NaOH is needed to titrate an unknown acid with a volume of 10.15mL. The final concentration of the resulting titrated sample is 0.163. Kindly explain how that value was found.
Solution X is a 400 mL benzoate/benzoic acid buffer solution with a pH of 3.49. If the concentration of benzoic acid present in solution X is 0.3 mol L–1, calculate the concentration of sodium benzoate (in mol L–1) present in solution X at 25 °C. The Ka of benzoic acid is 6.5E-5.
What is the pH of a buffer solution made by adding 0.41 g of NaC2H3O2 to 100. mL of 0.10 M HC2H302? Molar mass of NaC2H3O2 = 82.0 g/mol Ka of HC2H3O2 = 1.8x10-5 pH of buffer [?] pH of Buffer Enter