To estimate the mean amount of time children spend in physical activities daily, a researcher randomly selects 8 children and records the number of hours they spend in physical activities in one day. The numbers of hours are: 4.1, 1.2, 4.6, 2.4, 3.2, 1.8, 2.4, and 0.7. Obtain a 95% confidence interval of the mean number of hours that children spend in physical activities.
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To estimate the
a researcher randomly selects 8 children and records the number of hours they
spend in physical activities in one day. The numbers of hours are: 4.1, 1.2, 4.6,
2.4, 3.2, 1.8, 2.4, and 0.7. Obtain a 95% confidence interval of the mean number
of hours that children spend in physical activities.
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- A purchasing manager for a large university is investigating which brand of LCD projector to purchase to equip their classrooms. Of major concern is the longevity of the light bulbs used in the projectors. The purchasing manager has narrowed down the choice of projector to two brands, Infocus and Proxima, and wishes to determine if there is any difference between the two brands in the mean lifetime of the bulbs used. The purchasing manager obtained thirteen projectors of each brand for testing over the last several academic terms. The number of hours the bulbs lasted on each of the thirteen projectors is given in the table. Lifetimes of light bulbs (hours) Infocus 830, 867, 1013, 986, 819, 809, 691, 903, 673, 909, 957, 820, 715 Proxima 532, 718, 769, 806, 779, 970, 903, 1043, 947, 792, 841, 752, 689 Send data to calc... v Send data to Excel Assume that the two populations of lifetimes, are normally distributed and that the population variances are equal. Can we conclude, at the 0.01…A credit score is used by credit agencies (such as mortgage companies and banks) to assess the creditworthiness of individuals. Values range from 300 to 850, with a credit score over 700 considered to be a quality credit risk. According to a survey, the mean credit score is 704.5. A credit analyst wondered whether high-income individuals (incomes in excess of $100,000 per year) had higher credit scores. He obtained a random sample of 36 high-income individuals and found the sample mean credit score to be 714.9 with a standard deviation of 81.7. Conduct the appropriate test to determine if high-income individuals have higher credit scores at the a = 0.05 level of significance. State the null and alternative hypotheses. Ho: H V H1: H V (Type integers or decimals. Do not round.) Identify the t-statistic. to (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) Make a conclusion regarding the hypothesis. V the null hypothesis.…Let's use SPSS to run a one-sample t-test! Imagine that you are interested in whether the number of hours students in a statistics course work each week differs from the average number of hours reported by the general student body at ASU. Thankfully, you have a data set that consists of information from students in a statistics course, including how many hours they work each week ("workhours"). You also happen to know that the average number of hours worked each week by the general student population at ASU is 25. Use the data provided to conduct a one sample t-test in SPSS comparing the sample data to the population mean.. The dependent variable for your test should be "workhours". Based on your output, the average number of hours worked each week by a sample is ________ . Enter your answer rounded to two decimal places (i.e., 10.01, not 10.1, not 10.0, not 10.010).
- A study from 2014 found that adults in the US spend an average of 11 hours per day watching, reading, listening to or simply interacting with media. Researchers at UCLA suspect students spend less time engaging media. They grouped UCLA students by class section, randomly selected 20 class sections, and administered a survey to each student in those randomly selected class sections. The following data represents the mean time (in hours) per day spent engaging media for each of the randomly selected classes: 9.5 11.5 6.0 7.5 8 9.5 10.5 11 12 8.2 5 9.5 8.2 9.3 10.8 11 13 8.6 9.5 10.5 What would be the 99% Confidence Interval for mean time (in hours) spent per day engaging media for UCLA students. Do this "by hand", using appripriate symbols/formulas/tables.A purchasing manager for a large university is investigating which brand of LCD projector to purchase to equip their classrooms. Of major concern is the longevity of the light bulbs used in the projectors. The purchasing manager has narrowed down the choice of projector to two brands, Infocus and Proxima, and wishes to determine if there is any difference between the two brands in the mean lifetime of the bulbs used. The purchasing manager obtained eight projectors of each brand for testing over the last several academic terms. The number of hours the bulbs lasted on each of the eight projectors is given in the table. Lifetimes of light bulbs (hours) Infocus 745, 955, 1085, 756, 901, 839, 858, 931 Proxima 1012, 988, 957, 920, 878, 1130, 657, 743 Send data to calculator Assume that the two populations of lifetimes are normally distributed and that the population variances are equal. Can we conclude, at the 0.01 level of significance, that u, the mean lifetime of light bulbs in Infocus…A school had a lot of problems with student absences and wanted to try a intervention program to see if it encouraged students to come to school more often. As a trial, 26 students were split into two equal size groups. Group 1 would get the new intervention and Group 2 got no intervention. The mean- number of absences was calculated after one month for each group, as shown in the table below. What inference can be made about the results? Group 1 Group 2 3 5 3 1 3 2 3 4 1 3 2 1 2 3 3 4 2 5 1 3 1 6 4 2 1 2 Mean: 2.2 Mean: 3.2 Frequency200 Simulated Group Mean Differences Since the simulation shows FEW CASES OR Many Cases. where a mean difference of ___ or less occurred when the groups were re-randomized, it can be inferred that the mean difference observed in the study was VERY POSSIBLY OR VERY UNLIKELY due to the random assignment of participants into groups, so the results…
- A doctor in Oklahoma City wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 10% level of significance to test whether the average life span of heart disease patients in Oklahoma City differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 8.1, 1.2, 7, 11.5, 21, 2, 15.3, 19.2, 10.5, 15.4, 12.7, 15.3, 12.1, 7.5, 11.4, 16.4, 26.7, 14.6, 1.5, 16.3, 12.6, 0.8, 18.2, 4.2, 9.6, 21, 16.3, 2.7 Life Span of Patients Treated at Hospital 2: 17.6, 11.6, 16.8, 5.2, 6.7, 3.2, 13.8, 12.5, 0.9, 6, 14.3, 1.8, 14.8, 10, 5.8, 15.2, 10, 3.7, 11.4, 21.6, 12.9, 0.5, 9.2, 13.9, 10.9 ▼ Part 1 of 4 Life Span of Patients Treated at Hospital 3: 8.5, 2.3, 11, 7.4, 14.8, 5.8, 11, 3.4, 10.9, 1.1, 5.9, 21.6, 12.5, 0.1, 15.5, 15.4, 0.8, 7.7, 5.6, 12, 7.1 Life Span of Patients Treated at Hospital…A study from 2014 found that adults in the US spend an average of 11 hours per day watching, reading, listening to or simply interacting with media. Researchers at UCLA suspect students spend less time engaging media. They grouped UCLA students by class section, randomly selected 20 class sections, and administered a survey to each student in those randomly selected class sections. The following data represents the mean time (in hours) per day spent engaging media for each of the randomly selected classes: 9.5 11.5 6.0 7.5 8 9.5 10.5 11 12 8.2 5 9.5 8.2 9.3 10.8 11 13 8.6 9.5 10.5 What would be the calculator steps to find standard deviaton, rounded to 3 decimal places?The timed agility task was to take a stack of six yogurt cups, build a three-tiered pyramid and then return them to their initial stack. For 68 students, the mean time to accomplish this task was 8.07 seconds with a standard deviation of .695 seconds. Determine the value that would separate the fastest 20% of times from the rest of stacking times. The timed agility task was to take a stack of six yogurt cups, build a three-tiered pyramid and then return them to their initial stack. For 68 students, the mean time to accomplish this task was 8.07 seconds with a standard deviation of .695 seconds. Identify the value of z used to calculate the value that would separate the fastest 20% of times from the rest of stacking times.
