To determine the salt formed during a neutralization reaction, combine the anion formed by the dissociation of the acid and the cation formed by the dissociation of the base in a ratio that results in a neutral, ionic compound. For example, if you have a cation with a 1+ charge and an anion with a 2– charge, you will need two cations to balance the charge: [(1+ charge on cation)(2)]+[(2– charge on anion)(1)] = (+2) + (-2) = 0 Complete the following statements regarding the number of cations and anions present in the various ionic compounds. Match the numbers to the appropriate blanks in the sentences below. Make certain each sentence is complete before submitting your answer. • View Available Hint(s) Reset Help 1 1. The salt, magnesium bromide, is composed of magnesium ( Mg²+ ) 2 cation(s) and bromide ( Br¯ ) anion(s). 3 2. The salt, copper (III) sulfite, is composed of copper ( Cu³+ ) cation(s) and 4 sulfite ( SO3-) anion(s). 3. The salt, potassium dichromate, is composed of potassium ( K+ ) cation(s) and dichromate ( Cr2O7²- ) anion(s). 4. The salt, iron (II) phosphate, is composed of iron ( Fe2+ ) cation(s) and phosphate (PO4-) anion(s). 5. The salt, sodium hydroxide, is composed of sodium ( Na+ ) cation(s) and hydroxide ( OH- ) anion(s).

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To determine the salt formed during a neutralization reaction, combine the anion formed by the dissociation of the acid and the cation formed by the dissociation
of the base in a ratio that results in a neutral, ionic compound.
For example, if you have a cation with a 1+ charge and an anion with a 2– charge, you will need two cations to balance the charge:
[(1+ charge on cation)(2)]+[(2- charge on anion)(1)] = (+2) + (-2) = 0
%3D
Complete the following statements regarding the number of cations and anions present in the various ionic compounds.
Match the numbers to the appropriate blanks in the sentences below. Make certain each sentence is complete before submitting your answer.
• View Available Hint(s)
Reset
Help
1
1. The salt, magnesium bromide, is composed of
magnesium ( Mg²+ )
cation(s) and
bromide ( Br ) anion(s).
3
2. The salt, copper (III) sulfite, is composed of
copper ( Cu³+
) cation(s) and
4
2-
sulfite ( SO3 ) anion(s).
3. The salt, potassium dichromate, is composed of
potassium ( K+ ) cation(s)
and
dichromate ( Cr2 07 ) anion(s).
4. The salt, iron (II) phosphate, is composed of
iron (Fe2+ ) cation(s) and
phosphate (PO4 ) anion(s).
5. The salt, sodium hydroxide, is composed of
sodium ( Nat ) cation(s) and
hydroxide ( OH ) anion(s).
Transcribed Image Text:To determine the salt formed during a neutralization reaction, combine the anion formed by the dissociation of the acid and the cation formed by the dissociation of the base in a ratio that results in a neutral, ionic compound. For example, if you have a cation with a 1+ charge and an anion with a 2– charge, you will need two cations to balance the charge: [(1+ charge on cation)(2)]+[(2- charge on anion)(1)] = (+2) + (-2) = 0 %3D Complete the following statements regarding the number of cations and anions present in the various ionic compounds. Match the numbers to the appropriate blanks in the sentences below. Make certain each sentence is complete before submitting your answer. • View Available Hint(s) Reset Help 1 1. The salt, magnesium bromide, is composed of magnesium ( Mg²+ ) cation(s) and bromide ( Br ) anion(s). 3 2. The salt, copper (III) sulfite, is composed of copper ( Cu³+ ) cation(s) and 4 2- sulfite ( SO3 ) anion(s). 3. The salt, potassium dichromate, is composed of potassium ( K+ ) cation(s) and dichromate ( Cr2 07 ) anion(s). 4. The salt, iron (II) phosphate, is composed of iron (Fe2+ ) cation(s) and phosphate (PO4 ) anion(s). 5. The salt, sodium hydroxide, is composed of sodium ( Nat ) cation(s) and hydroxide ( OH ) anion(s).
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