To determine the half life of barium-137. The first-order rate law equation is shown here. At=Aoe^kt. At is the amount left at time t, Ao is the starting amount, and k is a rate constant that varies with every reaction. Given that the only requirement to solve for half-life is that At is one-half of Ao, if Ao is set as being 100%, or 1, the value of At is 0.5 Using your new values for Ao and At, solve the equation for t. The new equation is [ln(0.5)]/k=t half If k is known, you can solve for half-life and vice-versa.What is the value of k for this reaction???? Please provide neat and clean handwriting and clear image
To determine the half life of barium-137. The first-order rate law equation is shown here. At=Aoe^kt. At is the amount left at time t, Ao is the starting amount, and k is a rate constant that varies with every reaction. Given that the only requirement to solve for half-life is that At is one-half of Ao, if Ao is set as being 100%, or 1, the value of At is 0.5 Using your new values for Ao and At, solve the equation for t. The new equation is [ln(0.5)]/k=t half If k is known, you can solve for half-life and vice-versa.What is the value of k for this reaction???? Please provide neat and clean handwriting and clear image
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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To determine the half life of barium-137.
The first-order rate law equation is shown here. At=Aoe^kt. At is the amount left at time t, Ao is the starting amount, and k is a rate constant that varies with every reaction. Given that the only requirement to solve for half-life is that At is one-half of Ao, if Ao is set as being 100%, or 1, the value of At is 0.5
Using your new values for Ao and At, solve the equation for t. The new equation is [ln(0.5)]/k=t half
If k is known, you can solve for half-life and vice-versa.What is the value of k for this reaction????
Please provide neat and clean handwriting and clear image
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