To compare customer satisfaction levels of two competing internet service provider companies,174customers of Company 1 and 355 customers of Company 2 were randomly selected and askedto ratetheir internet service provider companies on a five-point scale, with 1 being least satisfiedand 5 mostsatisfied. The survey results are summarized in the following table:Company 1Company 2n1 = 174n2 = 355X1 = 3.51X2 = 3.24S1 = 0.51S2 = 0.524.1 Test at the 1% level of significance whether there is sufficient evidencetoconclude that Company 1 has a higher mean satisfaction rating than doesCompany 2. (Ensure you use the following steps: Null hypothesis,Alternativehypothesis, Test statistic, Critical value, Decision with reason,Interpretation4.2 Calculate the corresponding p-value4.3 Interpret the p-value (not a generalized definition from text book)

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Answered: To compare customer satisfaction levels…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Bank of America’s Consumer Spending Survey collected data on annual credit card charges in seven different categories of expenditures: transportation, groceries, dining out, household expenses, home furnishings, apparel, and entertainment. Using data from a sample of 42 credit card accounts, assume that each account was used to identify the annual credit card charges for groceries (population 1) and the annual credit card charges for dining out (population 2). Using the difference data, the sample mean difference was d= $850, and the sample standard deviation was sd= $1123.a. Formulate the null and alternative hypotheses to test for no difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.b. Use a .05 level of significance. Can you conclude that the population means dif-fer? What is the p-value?c. Which category, groceries or dining out, has a higher population mean annual credit card charge? What is the…
A contributor for the local newspaper is writing an article for the weekly fitness section. To prepare for the story, she conducts a study to compare the exercise habits of people who exercise in the morning to the exercise habits of people who work out in the afternoon or evening. She selects three different health centers from which to draw her samples. The 56 people she sampled who work out in the morning have a mean of 4.4 hours of exercise each week. The 63 people surveyed who exercise in the afternoon or evening have a mean of 4.2 hours of exercise each week. Assume that the weekly exercise times have a population standard deviation of 0.8 hours for people who exercise in the morning and 0.7 hours for people who exercise in the afternoon or evening. Let Population 1 be people who exercise in the morning and Population 2 be people who exercise in the afternoon or evening. Step 1 of 2: Construct a 99% confidence interval for the true difference between the mean amounts of…

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