To calculate the heat of combustion of naphthalene with calorimetric bomb, first the heat capacity of the calorimetric bomb is calculated. a) As a result of the burning of 1 g of Benzoic acid, a temperature rise of 2.63oC and a temperature of -3234.7 kJ / mol was released. Find the heat capacity of the calorimetric bomb. b) 6.4oC temperature difference was calculated as a result of burning 5 g of Naphthalene. Calculate the combustion temperature of naphthalene. (Molar mass of naphthalene: 128.17 g / mol)
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
To calculate the heat of combustion of naphthalene with calorimetric bomb, first the heat capacity of the calorimetric bomb is calculated.
a) As a result of the burning of 1 g of Benzoic acid, a temperature rise of 2.63oC and a temperature of -3234.7 kJ / mol was released. Find the heat capacity of the calorimetric bomb.
b) 6.4oC temperature difference was calculated as a result of burning 5 g of Naphthalene. Calculate the combustion temperature of naphthalene. (Molar mass of naphthalene: 128.17 g / mol)
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 2 images