To begin, change the angle of the cannon to 30°, and the initial speed to 15 m/s.Press the “cannon button”to launch the cannonball, and record these values. Note thatthe cannonball always starts atthe location (0, 0).Move the targetmeter so that the target is over the peak of the motion. Recordthe values from themeterat the peak. Use the time, initial values,and Equations 7 and 9 to calculate the x and y positions of the cannonball at this time. Then, move the target meter so that the target is over the very last dot in the motion (the instant it is landing). Recordthe values from the meter at this end point. Use the time, initial values, and Equations 7 and 9 to calculate the x and y positions of the cannonball at this time. Equation 7: x=vxit Equation 9: y=(vyit)+(-9.8m/s2)t2 Peak time: 0.76s Peak range: 9.93m Peak Height: 2.87m End time: 1.53s End range: 19.86m End height: 0m

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To begin, change the angle of the cannon to 30°, and the initial speed to 15 m/s.Press the “cannon button”to launch the cannonball, and record these values. Note thatthe cannonball always starts atthe location (0, 0).Move the targetmeter so that the target is over the peak of the motion. Recordthe values from themeterat the peak. Use the time, initial values,and Equations 7 and 9 to calculate the x and y positions of the cannonball at this time. Then, move the target meter so that the target is over the very last dot in the motion (the instant it is landing). Recordthe values from the meter at this end point. Use the time, initial values, and Equations 7 and 9 to calculate the x and y positions of the cannonball at this time.

Equation 7: x=vxit

Equation 9: y=(vyit)+(-9.8m/s2)t2

Peak time: 0.76s
Peak range: 9.93m
Peak Height: 2.87m

End time: 1.53s
End range: 19.86m
End height: 0m

I've tried plugging in 15m/s for vxi and vyi but this gives different answers for x(range) and y(height) than I recorded from the simulation. How do I answer these?

Expert Solution
Step 1

Given:

   Angle made by the cannon, θ = 30°

   Initial speed, vi =15 m/s

   Peak time, tp = 0.76 s

   End time, tend = 1.53 s

Equation-7 : x =vixt

Equation-9 : y = viy t +12×-9.8m/s2 t2 (note: there is a 1/2 term missing in your equation, without this correction your values for y does not tally.

Using equations 7 & 9 calculate the x and y positions of the cannonball

     a) when the target is at the peak of the motion. 

     b) when the target is at the very last dot in the motion.

 

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