TL-2 A single rectangular uniform wire loop swings from a hinge on the side that lies along the x axis shownin the figure below. There is a current I around the loop as shown in the figure. In the region of the loopthere is a uniform magnetic field B-0.175T that points straight up. The interaction of the loop's dipolemoment with the magnetic field causes the loop to be held at rest in the position shown in the figure25.0° from the vertical. The lengths and masses of the sides of the loop are: L₁-Ly 0.900m, massesm₁ m, 0.0450kg, L-L-0.300m and masses m₂ m 0.0150kga) Where is the center of mass of the loop?Draw the free body diagram for the loopon the figure below.25.0⁰yB-0.175TZ0.900m 10.300m TL-2 (Cont.)b) Find the magnitude of the torque about the origin on the current loop due to the total weight of theloop (which acts thru the center of mass of the loop).c) Describe symbolically the magnetic torque on the loop using 7 = μxB.d) Apply Newton's second law of rotation Thet-la to find the current needed to hold the loop at rest inthe position shown.

Answered: Image /qna-images/answer/a522c2a7-ef82-4e04-a873-7c3d8c505d85.jpg

TL-2 A single rectangular uniform wire loop swings from a hinge on the side that lies along the x axis shown in the figure below. There is a current I around the loop as shown in the figure. In the region of the loop there is a uniform magnetic field B-0.175T that points straight up. The interaction of the loop's dipole moment with the magnetic field causes the loop to be held at rest in the position shown in the figure 25.0° from the vertical. The lengths and masses of the sides of the loop are: L₁-L,-0.900m, masses m, m, 0.0450kg, L-L-0.300m and masses m₂ m -0.0150kg a) Where is the center of mass of the loop? Draw the free body diagram for the loop on the figure below. 25.00 y B-0.175T 0.900m 1 0.300m

TL-2 A single rectangular uniform wire loop swings from a hinge on the side that lies along the x axis shown in the figure below. There is a current I around the loop as shown in the figure. In the region of the loop there is a uniform magnetic field B-0.175T that points straight up. The interaction of the loop's dipole moment with the magnetic field causes the loop to be held at rest in the position shown in the figure 25.0° from the vertical. The lengths and masses of the sides of the loop are: L₁-L,-0.900m, masses m, m, 0.0450kg, L-L-0.300m and masses m₂ m -0.0150kg a) Where is the center of mass of the loop? Draw the free body diagram for the loop on the figure below. 25.00 y B-0.175T 0.900m 1 0.300m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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