tire company measures the tread on newly-produced tires and finds that they are normally distributed with a mean depth of 0.98mm and a standard deviation
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A tire company measures the tread on newly-produced tires and finds that they are
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- A certain grade egg must weigh at least 2.0 Oz. If the weights of eggs are normally distributed with a mean of 1.5oz. And a standard deviation of 0.4oz, approximately how many eggs would you expect to weigh more than 2oz?In the 1800s, German physician Carl Reinhold, took millions of axillary (i.e. armpit) temperatures from soldiers. This study established that body temperature is normally distributed and the standard normal human body temperature is 98.6°F with a standard deviation of 0.72 °F. In a recent study, American researchers obtained 5,000 axillary temperatures from a Los Angeles hospital. The mean of these temperature readings was 97.9 °F. Assuming a Type I error risk of no more than 5%, did the findings support the theory that human, body temperature has decreased since the 1800s? What is the Z crit?The weights of 1,000 men in a certain town follow a normal distribution with a mean of 150 pounds and a standard deviation of 15 pounds. From the data, we can conclude that the number of men weighing more than 165 pounds is about , and the number of men weighing less than 135 pounds is about .
- The weights of an adult female population of killer whales are approximately normally distributed with a mean of 18,000 pounds and a standard deviation of 4,000 pounds. The weights of an adult male population of killer whales are approximately normally distributed with a mean of 30,000 pounds and a standard deviation of 6,000 pounds. A certain adult male killer whale weighs 24,000 pounds. This adult male would have the same z-score weight as a female killer whale whose weight, in kilograms, is equal to which of the following? Select one: 1. 24,000 2. 30,000 3. 36,000 4. 21,000 5. 14,000Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all adults. (Accommodating 100% of adults would require very wide seats that would be much too expensive.) Assume adults have hip widths that are normally distributed with a mean of 13.6 in. and a standard deviation of 1.2 in. Find P99. That is, find the hip width for adults that separates the smallest 99% from the largest 1%. What is the maximum hip width that is required to satisfy the requirement of fitting 99% of adults? in. (Round to one decimal place as needed.)Engineers want to design seats in commercial aircraft so that they are wide enough to fit 90%of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.7in. and a standard deviation of 1.2in. Find P90. That is, find the hip breadth for men that separates the smallest 90% from the largest 10%. The hip breadth for men that separates the smallest 90%from the largest 10% is P90=nothing in. (Round to one decimal place as needed.)
- The weights for a baby boy is normally distributed with a mean score of 7lbs and a standard deviation of 0.8lbs. determine the following:Q1 1. The following spinner was spun 38 times. What is the probability of spinning A 16 times? Insert ImageCompanies who design furniture for elementary school classrooms produce a variety of sizes for children of different ages. Suppose the heights of kindergarten children are normally distributed with a mean of 97 cm and a standard deviation of 4.9 cm. What proportion of kindergarten children should the company expect to be less than 91 cm tall?
- Engineers want to design seats in commercial aircraft so that they are wide enough to fit 90% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.2in. and a standard deviation of1.1in. FindP90. That is, find the hip breadth for men that separates the smallest 90% from the largest 10%.According to a recent study, the carapace length for adult males of a certain species of tarantula are normally distributed with a mean of μ=17.47 mm and a standard deviation of σ=1.95 mm. Complete parts (a) through (d) below. a. Find the percentage of the tarantulas that have a carapace length between 15mm and 16 mm. The percentage of the tarantulas that have a carapace length between 15 and 16 is nothing %.A nursery sells lime trees that have normally distributed heights with a mean of 2 ft and a standard deviation of 0.3 ft. Find the probability that a randomly selected tree is between 1 and 2 ft.
