Time between accidents in an industrial setting are exponentially distributed with a mean of 100,000 man-hours of operation. Determine the probability that next accident will occur before 80,000 man-hours of operation. Pr(Next accident is before 80000 hrs)=

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Time between accidents in an industrial setting are exponentially distributed with a mean of 100,000 man-hours
of operation. Determine the probability that next accident will occur before 80,000 man-hours of operation.
Pr(Next accident is before 80000 hrs)=
Transcribed Image Text:Time between accidents in an industrial setting are exponentially distributed with a mean of 100,000 man-hours of operation. Determine the probability that next accident will occur before 80,000 man-hours of operation. Pr(Next accident is before 80000 hrs)=
Quality characteristic of a product is normally distributed with a mean value of 10.002 mm and standard
deviation of 0.007 mm. Design tolerances for this quality characteristic are 10+0.020 mm.
a) Determine the probability that the tolerances will be violated.
Pr(Tolerances Violated)=
b) Determine the number of products that will be out of tolerance if 10,000 parts are manufactured.
Number of Bad Parts=
c) What is one way to minimize the number of parts produced out of tolerances by setting up the machine
and how much the number will be reduced?
New Number of Bad Parts=
Transcribed Image Text:Quality characteristic of a product is normally distributed with a mean value of 10.002 mm and standard deviation of 0.007 mm. Design tolerances for this quality characteristic are 10+0.020 mm. a) Determine the probability that the tolerances will be violated. Pr(Tolerances Violated)= b) Determine the number of products that will be out of tolerance if 10,000 parts are manufactured. Number of Bad Parts= c) What is one way to minimize the number of parts produced out of tolerances by setting up the machine and how much the number will be reduced? New Number of Bad Parts=
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