Tigure is bound by are perpendicular to the y-axis are squares. Algebraically, what is the area of each square? y

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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**Base of the Three-Dimensional Figure and Vertical Cross Sections**

The base of a three-dimensional figure is bounded by the line \( x = y + 4 \). Vertical cross-sections that are perpendicular to the y-axis are squares.

**Question:**
Algebraically, what is the area of each square?

**Graph Explanation:**
The provided graph shows the line \( x = y + 4 \) on a standard coordinate plane. The area between the x-axis and this line, extending from \( x = 0 \) to \( y = -4 \), forms a right triangle which is shaded.

**Mathematical Options:**
1. \( A = (y + 4)^2 \) ∘
2. \( A = (y + 4) \) ∘
3. \( A = 2(y + 4)^2 \) ∘
4. \( A = \frac{1}{2}(y + 4)^2 \) ∘

Choose the correct algebraic expression for the area of each square from the options provided above.
Transcribed Image Text:**Base of the Three-Dimensional Figure and Vertical Cross Sections** The base of a three-dimensional figure is bounded by the line \( x = y + 4 \). Vertical cross-sections that are perpendicular to the y-axis are squares. **Question:** Algebraically, what is the area of each square? **Graph Explanation:** The provided graph shows the line \( x = y + 4 \) on a standard coordinate plane. The area between the x-axis and this line, extending from \( x = 0 \) to \( y = -4 \), forms a right triangle which is shaded. **Mathematical Options:** 1. \( A = (y + 4)^2 \) ∘ 2. \( A = (y + 4) \) ∘ 3. \( A = 2(y + 4)^2 \) ∘ 4. \( A = \frac{1}{2}(y + 4)^2 \) ∘ Choose the correct algebraic expression for the area of each square from the options provided above.
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