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A tightly wound circular coil has 50 turns, each of radius 0.10 m. A uniform magnetic field is turned on along a direction perpendicular to the plane of the coils. If the field increases linearly from 0 T to 0.6 T in 0.20 s, what emf is induced in the coil?
Hint: Φ= BA cosθ

cos(0⁰) =1

Then, Φ= BA;

Induced emf is caused by a chane in magnetic flux<=> emf = -N ∆Φ/∆t
The change in the magnetic flux, ∆Φ, is caused by the change in the strength of the magnetic field, B.
∆Φ =∆(B.A)= A . ∆B = A . ( B_f-Bi)

∆t =0.2 s
A= area of the coil = πr²

Group of answer choices

A) 4.71 V

B) 0.94 V

C) 0.1 V

D) 0.5 V

Please show how you solved and provide explanations. I am struggling in this section of physics, so I am very greatful for your guidance.

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