College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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#2 please show work so I can understand. Thank you!
![**Physics Homework: Energy and Motion**
**2. Refer to figure 2. The 10.0 kg green cart travels down a ramp — from point A to B. Calculate its starting potential energy, kinetic energy at the bottom of the ramp, and its velocity coming off the bottom of the ramp. If the cart coasts from points B to C, did it do any work? How far up the 2nd ramp does the cart go as measured from the ground?**
*Figure 2:*
- **Description:** This figure depicts a cart initially placed at point A on the first ramp and traveling down to point B at the base of the first ramp. Subsequently, it coasts horizontally from point B to point C and up the second ramp.
- **Details:**
- Point A is positioned 10.0 m above the ground level before descending the sloped ramp to point B.
- The two ramps form right angles with the ground, creating a triangular shape with the horizontal ground line which extends from B to C at the base.
- From C, the second ramp rises at the same angle as the first but in the opposite direction.
**3. Refer to figure 3. How fast must the cart go in order to complete the loop-to-loop successfully?**
*Figure 3:*
- **Description:** This figure illustrates a green cart approaching a loop-the-loop structure.
- **Details:**
- The loop has a diameter of 20.0 meters.
- The diameter is prominently displayed by a vertical line measuring 20.0 meters.
- The cart is assumed to approach the loop from a flat horizontal track.
**Considerations for Calculations:**
1. Potential Energy at A (PE):
\[
PE = mgh
\]
where:
\( m \) = 10.0 kg (mass of the cart)
\( g \) = 9.8 m/s² (acceleration due to gravity)
\( h \) = 10.0 m (height at point A)
2. Kinetic Energy at B and Velocity:
Because all potential energy converts into kinetic energy at the bottom of the ramp:
\[
KE = PE
\]
The kinetic energy (KE) at point B can be calculated using:
\[
KE = \frac{1}{2}mv^2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb17382d2-9e6c-40e2-a6b7-8172ebf93e2c%2Fea94eaf3-07df-4cc9-bd99-3d8a874113e0%2Faq65uei.jpeg&w=3840&q=75)
Transcribed Image Text:**Physics Homework: Energy and Motion**
**2. Refer to figure 2. The 10.0 kg green cart travels down a ramp — from point A to B. Calculate its starting potential energy, kinetic energy at the bottom of the ramp, and its velocity coming off the bottom of the ramp. If the cart coasts from points B to C, did it do any work? How far up the 2nd ramp does the cart go as measured from the ground?**
*Figure 2:*
- **Description:** This figure depicts a cart initially placed at point A on the first ramp and traveling down to point B at the base of the first ramp. Subsequently, it coasts horizontally from point B to point C and up the second ramp.
- **Details:**
- Point A is positioned 10.0 m above the ground level before descending the sloped ramp to point B.
- The two ramps form right angles with the ground, creating a triangular shape with the horizontal ground line which extends from B to C at the base.
- From C, the second ramp rises at the same angle as the first but in the opposite direction.
**3. Refer to figure 3. How fast must the cart go in order to complete the loop-to-loop successfully?**
*Figure 3:*
- **Description:** This figure illustrates a green cart approaching a loop-the-loop structure.
- **Details:**
- The loop has a diameter of 20.0 meters.
- The diameter is prominently displayed by a vertical line measuring 20.0 meters.
- The cart is assumed to approach the loop from a flat horizontal track.
**Considerations for Calculations:**
1. Potential Energy at A (PE):
\[
PE = mgh
\]
where:
\( m \) = 10.0 kg (mass of the cart)
\( g \) = 9.8 m/s² (acceleration due to gravity)
\( h \) = 10.0 m (height at point A)
2. Kinetic Energy at B and Velocity:
Because all potential energy converts into kinetic energy at the bottom of the ramp:
\[
KE = PE
\]
The kinetic energy (KE) at point B can be calculated using:
\[
KE = \frac{1}{2}mv^2
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