Three solid, uniform boxes are aligned as in the figure below. Find the X- and y-coordinates (in m) of the center of mass of the three boxes, measured from the bottom left corner of box A. (Consider the three-box system.) HINT x cm Y cm || Origin m m 0.360 m A 0.750 kg 0.420 m B 1.00 kg 0.240 m с 0.650 kg 0.410 m X
Three solid, uniform boxes are aligned as in the figure below. Find the X- and y-coordinates (in m) of the center of mass of the three boxes, measured from the bottom left corner of box A. (Consider the three-box system.) HINT x cm Y cm || Origin m m 0.360 m A 0.750 kg 0.420 m B 1.00 kg 0.240 m с 0.650 kg 0.410 m X
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
Three solid, uniform boxes are aligned as shown in the figure. Find the x- and y-coordinates (in meters) of the center of mass of the three boxes, measured from the bottom left corner of box A. (Consider the three-box system.)
**Diagram Explanation:**
The diagram shows three adjacent boxes labeled A, B, and C from left to right. The x- and y-coordinate system is indicated, with the origin at the bottom left corner of box A.
- **Box A**:
- Width: 0.360 m
- Mass: 0.750 kg
- **Box B**:
- Width: 0.420 m
- Mass: 1.00 kg
- **Box C**:
- Width: 0.240 m
- Height: 0.410 m
- Mass: 0.650 kg
**Objective:**
To calculate the center of mass (x_cm, y_cm) of the entire three-box system.
**Formulas:**
The center of mass coordinates \((x_{cm}, y_{cm})\) are given by:
\[
x_{cm} = \frac{(m_1 \cdot x_1) + (m_2 \cdot x_2) + (m_3 \cdot x_3)}{m_1 + m_2 + m_3}
\]
\[
y_{cm} = \frac{(m_1 \cdot y_1) + (m_2 \cdot y_2) + (m_3 \cdot y_3)}{m_1 + m_2 + m_3}
\]
where \(m_1, m_2, m_3\) are the masses of boxes A, B, and C respectively, and \((x_1, y_1), (x_2, y_2), (x_3, y_3)\) are the coordinates of the centers of the individual boxes.
**Inputs for Calculation:**
- Box A center: (\(0.180, 0\))
- Box B center: (\(0.570, 0\))
- Box C center: (\(0.810, 0.205\))
**Solution:**
Calculate \(x_{cm}\) and \(y_{cm}\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F08aa0b19-cba0-4fd4-b1f6-356b8c0f7ad5%2Fc98ceb89-b4d1-4bc7-b952-9da709bf5674%2F15pmbuh_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Three solid, uniform boxes are aligned as shown in the figure. Find the x- and y-coordinates (in meters) of the center of mass of the three boxes, measured from the bottom left corner of box A. (Consider the three-box system.)
**Diagram Explanation:**
The diagram shows three adjacent boxes labeled A, B, and C from left to right. The x- and y-coordinate system is indicated, with the origin at the bottom left corner of box A.
- **Box A**:
- Width: 0.360 m
- Mass: 0.750 kg
- **Box B**:
- Width: 0.420 m
- Mass: 1.00 kg
- **Box C**:
- Width: 0.240 m
- Height: 0.410 m
- Mass: 0.650 kg
**Objective:**
To calculate the center of mass (x_cm, y_cm) of the entire three-box system.
**Formulas:**
The center of mass coordinates \((x_{cm}, y_{cm})\) are given by:
\[
x_{cm} = \frac{(m_1 \cdot x_1) + (m_2 \cdot x_2) + (m_3 \cdot x_3)}{m_1 + m_2 + m_3}
\]
\[
y_{cm} = \frac{(m_1 \cdot y_1) + (m_2 \cdot y_2) + (m_3 \cdot y_3)}{m_1 + m_2 + m_3}
\]
where \(m_1, m_2, m_3\) are the masses of boxes A, B, and C respectively, and \((x_1, y_1), (x_2, y_2), (x_3, y_3)\) are the coordinates of the centers of the individual boxes.
**Inputs for Calculation:**
- Box A center: (\(0.180, 0\))
- Box B center: (\(0.570, 0\))
- Box C center: (\(0.810, 0.205\))
**Solution:**
Calculate \(x_{cm}\) and \(y_{cm}\)
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