Three point charges are located on the x-axis. The first charge, q1 = +10 µC, is at x = -1.0 m. The second charge, q2 = +20 µC, is at the origin. The third charge, q3 = - 30 µC, is located at x = +2.0 m. What is the magnitude of the net electric field at (+1.0 m, 0) due to the three charges

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A: q1 = 8 μC q2 = 1 μC Q = -4 μC Distance between q1 and Q , d1 = 5 cm = 0.05 m Distance between q2 and…

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A: solution:Given that Q = 3.29 micro C R = 8.41 cm

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A: let the two charges        q1= 8.724 x 10-6 c        q2= 1.327 x 10-6 c distance = d = 1.01 cm

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Q: magnitude direction BµC 60.0⁰ A μC 0.500 m (a) Three point charges, A = 2.15 μC, B = 6.95 μC, and C=…

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A: Given data:  Q1=7.4 μC = 7.4×10-6 C  Q2=-7.8 μC = -7.8×10-6 C  Q3=-5.0 μC = -5.0×10-6 C  Side of…

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A: Step 1:The electric field is 8×106N/CRadius is 3cm is 0.03mStep 2:The formula for the electric field…

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.