Three point charges are arranged as shown in the figure below. Find the magnitude and direction of the electric force on the particle q = 5.12 nC at the origin. (Let r12 = 0.260 m.) magnitude N direction counterclockwise from the +x axis 6.00 nC P12 9 0.100 m -3.00 nC

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### Problem Statement

Three point charges are arranged as shown in the figure below. Find the magnitude and direction of the electric force on the particle \( q = 5.12 \, \text{nC} \) at the origin. (Let \( r_{12} = 0.260 \, \text{m} \)).

#### Required:
- **Magnitude**: [Text Box] \( \text{N} \)
- **Direction**: [Text Box] \( \degree \, \text{counterclockwise from the +x axis} \)

### Diagram Explanation

The diagram below illustrates the arrangement of three point charges:
- A positively charged particle \( q = 5.12 \, \text{nC} \) positioned at the origin of the coordinate system.
- Along the x-axis at \( r_{12} = 0.260 \, \text{m} \) from the origin is a positively charged particle \( 6.00 \, \text{nC} \).
- Along the negative y-axis at \( 0.100 \, \text{m} \) from the origin is a negatively charged particle \( -3.00 \, \text{nC} \).

### Diagram

```
        y
        ↑
        |
        q
        +
        (5.12 nC, origin)
        |
        0.100 m
        |
        -3.00 nC
        • ( -0.100 m on y-axis)
        |
        |
        |
        +------------------------------> x
        (r12=0.260 m)
        • 6.00 nC (on x-axis)
```

This diagram shows the coordinates and charges' placement:
- The origin has a charge of \( 5.12 \, \text{nC} \).
- The point on the x-axis 0.260 m from the origin has a charge of \( 6.00 \, \text{nC} \).
- The negative y-axis 0.100 m from the origin has a charge of \( -3.00 \, \text{nC} \).

Use this diagram to calculate the resultant electric force on the particle at the origin.
Transcribed Image Text:### Problem Statement Three point charges are arranged as shown in the figure below. Find the magnitude and direction of the electric force on the particle \( q = 5.12 \, \text{nC} \) at the origin. (Let \( r_{12} = 0.260 \, \text{m} \)). #### Required: - **Magnitude**: [Text Box] \( \text{N} \) - **Direction**: [Text Box] \( \degree \, \text{counterclockwise from the +x axis} \) ### Diagram Explanation The diagram below illustrates the arrangement of three point charges: - A positively charged particle \( q = 5.12 \, \text{nC} \) positioned at the origin of the coordinate system. - Along the x-axis at \( r_{12} = 0.260 \, \text{m} \) from the origin is a positively charged particle \( 6.00 \, \text{nC} \). - Along the negative y-axis at \( 0.100 \, \text{m} \) from the origin is a negatively charged particle \( -3.00 \, \text{nC} \). ### Diagram ``` y ↑ | q + (5.12 nC, origin) | 0.100 m | -3.00 nC • ( -0.100 m on y-axis) | | | +------------------------------> x (r12=0.260 m) • 6.00 nC (on x-axis) ``` This diagram shows the coordinates and charges' placement: - The origin has a charge of \( 5.12 \, \text{nC} \). - The point on the x-axis 0.260 m from the origin has a charge of \( 6.00 \, \text{nC} \). - The negative y-axis 0.100 m from the origin has a charge of \( -3.00 \, \text{nC} \). Use this diagram to calculate the resultant electric force on the particle at the origin.
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