Three point charges are arranged as shown in the figure below. Find the magnitude and direction of the electric force on the particle q = 5.12 nC at the origin. (Let r12 = 0.260 m.) magnitude N direction counterclockwise from the +x axis 6.00 nC P12 9 0.100 m -3.00 nC
Three point charges are arranged as shown in the figure below. Find the magnitude and direction of the electric force on the particle q = 5.12 nC at the origin. (Let r12 = 0.260 m.) magnitude N direction counterclockwise from the +x axis 6.00 nC P12 9 0.100 m -3.00 nC
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![### Problem Statement
Three point charges are arranged as shown in the figure below. Find the magnitude and direction of the electric force on the particle \( q = 5.12 \, \text{nC} \) at the origin. (Let \( r_{12} = 0.260 \, \text{m} \)).
#### Required:
- **Magnitude**: [Text Box] \( \text{N} \)
- **Direction**: [Text Box] \( \degree \, \text{counterclockwise from the +x axis} \)
### Diagram Explanation
The diagram below illustrates the arrangement of three point charges:
- A positively charged particle \( q = 5.12 \, \text{nC} \) positioned at the origin of the coordinate system.
- Along the x-axis at \( r_{12} = 0.260 \, \text{m} \) from the origin is a positively charged particle \( 6.00 \, \text{nC} \).
- Along the negative y-axis at \( 0.100 \, \text{m} \) from the origin is a negatively charged particle \( -3.00 \, \text{nC} \).
### Diagram
```
y
↑
|
q
+
(5.12 nC, origin)
|
0.100 m
|
-3.00 nC
• ( -0.100 m on y-axis)
|
|
|
+------------------------------> x
(r12=0.260 m)
• 6.00 nC (on x-axis)
```
This diagram shows the coordinates and charges' placement:
- The origin has a charge of \( 5.12 \, \text{nC} \).
- The point on the x-axis 0.260 m from the origin has a charge of \( 6.00 \, \text{nC} \).
- The negative y-axis 0.100 m from the origin has a charge of \( -3.00 \, \text{nC} \).
Use this diagram to calculate the resultant electric force on the particle at the origin.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0a5ac3c6-e4ab-423a-91e1-ff33bdae0d07%2Fc628a40c-7ce3-4022-8d37-846488c784e4%2Fkbm3eh_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Statement
Three point charges are arranged as shown in the figure below. Find the magnitude and direction of the electric force on the particle \( q = 5.12 \, \text{nC} \) at the origin. (Let \( r_{12} = 0.260 \, \text{m} \)).
#### Required:
- **Magnitude**: [Text Box] \( \text{N} \)
- **Direction**: [Text Box] \( \degree \, \text{counterclockwise from the +x axis} \)
### Diagram Explanation
The diagram below illustrates the arrangement of three point charges:
- A positively charged particle \( q = 5.12 \, \text{nC} \) positioned at the origin of the coordinate system.
- Along the x-axis at \( r_{12} = 0.260 \, \text{m} \) from the origin is a positively charged particle \( 6.00 \, \text{nC} \).
- Along the negative y-axis at \( 0.100 \, \text{m} \) from the origin is a negatively charged particle \( -3.00 \, \text{nC} \).
### Diagram
```
y
↑
|
q
+
(5.12 nC, origin)
|
0.100 m
|
-3.00 nC
• ( -0.100 m on y-axis)
|
|
|
+------------------------------> x
(r12=0.260 m)
• 6.00 nC (on x-axis)
```
This diagram shows the coordinates and charges' placement:
- The origin has a charge of \( 5.12 \, \text{nC} \).
- The point on the x-axis 0.260 m from the origin has a charge of \( 6.00 \, \text{nC} \).
- The negative y-axis 0.100 m from the origin has a charge of \( -3.00 \, \text{nC} \).
Use this diagram to calculate the resultant electric force on the particle at the origin.
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