Three particles of masses 50 g, 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1 m (as shown in the figure). The (x, y) coordinates of the centre of mass will be : Y m = 150 g 3. 50 g = m, m2= 100 g 60°
Three particles of masses 50 g, 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1 m (as shown in the figure). The (x, y) coordinates of the centre of mass will be : Y m = 150 g 3. 50 g = m, m2= 100 g 60°
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Introduction And Vectors
Section: Chapter Questions
Problem 62P
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![Three particles of masses 50 g, 100 g and 150 g are placed
at the vertices of an equilateral triangle of side 1 m (as
shown in the figure). The (x, y) coordinates of the centre of
mass will be :
m3 = 150 g
%3D
50 g = m,
m, = 100 g
60°
0.5 m
1.0 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5a60e22c-11ca-40ed-b938-6612cceb9a39%2F6a7e467d-4aa7-4a29-91ad-2aafcc399499%2Fbq5jmir_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Three particles of masses 50 g, 100 g and 150 g are placed
at the vertices of an equilateral triangle of side 1 m (as
shown in the figure). The (x, y) coordinates of the centre of
mass will be :
m3 = 150 g
%3D
50 g = m,
m, = 100 g
60°
0.5 m
1.0 m
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