Three Charges are arranged as shown. All charges are shown. Point X is indicating a location where no charge is located. 3) The direction of the electric field at point X is in which quadrant? a. Up and Right b. Up and Left c. Down and Left d. e. It is Zero 4) The electric potential at Point X is closest to Down and Right

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**Educational Content on Electric Fields and Potentials**

In the provided diagram, we have three charges arranged strategically. Each charge has a magnitude of 1 Coulomb (C), with the signs specified in the illustration. Point X marks a location where no charge is present. Distances between the charges and Point X are clearly indicated for analysis.

### Diagram Explanation
- **Arrangement**: Two positive charges (+1 C) and one negative charge (-1 C) are positioned on the plane.
- **Distances**: 
  - A positive charge is 2 meters to the right of Point X.
  - The second positive charge is 2 meters below the first positive charge.
  - The negative charge is 2 meters to the right of the second positive charge and 4 meters to the right of Point X.

### Questions and Explanations

3) **The direction of the electric field at point X is in which quadrant?**
   - Consider the directions and interactions of electric fields due to each charge:
     - Positive charges repel, creating an electric field directed away from them.
     - The negative charge attracts, directing the field towards it.
   - Answer options:
     - a. Up and Right
     - b. Up and Left
     - c. Down and Left
     - d. Down and Right
     - e. It is Zero

4) **The electric potential at Point X is closest to:**
   - Calculate the potential using \( V = k\frac{q}{r} \) for each charge, where \( k \) is Coulomb’s constant, \( q \) is the charge, and \( r \) is the distance.
   - Sum the potentials from each charge to find the net potential.
   - Answer options:
     - a. Zero
     - b. \(2.3 \times 10^9 \, \text{V}\)
     - c. \(3.9 \times 10^9 \, \text{V}\)
     - d. \(4.5 \times 10^9 \, \text{V}\)
     - e. \(5.4 \times 10^9 \, \text{V}\)

This exercise demonstrates the concepts of electric fields and potentials in a system of point charges, allowing for practical understanding through calculation and vector analysis.
Transcribed Image Text:**Educational Content on Electric Fields and Potentials** In the provided diagram, we have three charges arranged strategically. Each charge has a magnitude of 1 Coulomb (C), with the signs specified in the illustration. Point X marks a location where no charge is present. Distances between the charges and Point X are clearly indicated for analysis. ### Diagram Explanation - **Arrangement**: Two positive charges (+1 C) and one negative charge (-1 C) are positioned on the plane. - **Distances**: - A positive charge is 2 meters to the right of Point X. - The second positive charge is 2 meters below the first positive charge. - The negative charge is 2 meters to the right of the second positive charge and 4 meters to the right of Point X. ### Questions and Explanations 3) **The direction of the electric field at point X is in which quadrant?** - Consider the directions and interactions of electric fields due to each charge: - Positive charges repel, creating an electric field directed away from them. - The negative charge attracts, directing the field towards it. - Answer options: - a. Up and Right - b. Up and Left - c. Down and Left - d. Down and Right - e. It is Zero 4) **The electric potential at Point X is closest to:** - Calculate the potential using \( V = k\frac{q}{r} \) for each charge, where \( k \) is Coulomb’s constant, \( q \) is the charge, and \( r \) is the distance. - Sum the potentials from each charge to find the net potential. - Answer options: - a. Zero - b. \(2.3 \times 10^9 \, \text{V}\) - c. \(3.9 \times 10^9 \, \text{V}\) - d. \(4.5 \times 10^9 \, \text{V}\) - e. \(5.4 \times 10^9 \, \text{V}\) This exercise demonstrates the concepts of electric fields and potentials in a system of point charges, allowing for practical understanding through calculation and vector analysis.
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