Three charged particles are located at the corners of an equilateral triangle as shown in the figure below (let q = 1.80 μC, and L = 0.710 m). Calculate the total electric force on the 7.00-μC charge. N • (counterclockwise from the +x axis) magnitude direction 7.00 μ. 60,0⁰ L 00 C

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**Title: Electric Force on Charged Particles in an Equilateral Triangle**

**Description:**
In this problem, we examine the interaction of charged particles located at the corners of an equilateral triangle. The goal is to calculate the total electric force on the 7.00-μC charge.

**Given:**
- Charge \( q = 1.80 \, \mu\text{C} \)
- Side length \( L = 0.710 \, \text{m} \)

**Figure Explanation:**
- The setup forms an equilateral triangle with each side labeled \( L \).
- Three charges are placed at the triangle’s vertices:
  - Two positive charges are \( 7.00 \, \mu\text{C} \) and \( 1.80 \, \mu\text{C} \).
  - One negative charge is \( -4.00 \, \mu\text{C} \).
- The angle between the x-axis and the line connecting the 7.00-μC charge and the 1.80-μC charge is \( 60.0^\circ \).

**Objective:**
- Calculate the total electric force on the 7.00-μC charge. This involves determining both the magnitude (in Newtons, N) and the direction (counterclockwise from the +x axis in degrees).

This problem involves principles of electrostatics and vector addition to solve for the resultant force vector on the specified charge.
Transcribed Image Text:**Title: Electric Force on Charged Particles in an Equilateral Triangle** **Description:** In this problem, we examine the interaction of charged particles located at the corners of an equilateral triangle. The goal is to calculate the total electric force on the 7.00-μC charge. **Given:** - Charge \( q = 1.80 \, \mu\text{C} \) - Side length \( L = 0.710 \, \text{m} \) **Figure Explanation:** - The setup forms an equilateral triangle with each side labeled \( L \). - Three charges are placed at the triangle’s vertices: - Two positive charges are \( 7.00 \, \mu\text{C} \) and \( 1.80 \, \mu\text{C} \). - One negative charge is \( -4.00 \, \mu\text{C} \). - The angle between the x-axis and the line connecting the 7.00-μC charge and the 1.80-μC charge is \( 60.0^\circ \). **Objective:** - Calculate the total electric force on the 7.00-μC charge. This involves determining both the magnitude (in Newtons, N) and the direction (counterclockwise from the +x axis in degrees). This problem involves principles of electrostatics and vector addition to solve for the resultant force vector on the specified charge.
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