Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 3.00 µC, and L = 0.650 m. 7.00 µC L 60.0° -4.00 μC 0 (a) Calculate the electric field at the position of charge q due to the 7.00-µC and –4.00-µC charges. kN/C Î + kN/C ĵ (b) Use your answer to part (a) to determine the force on charge q. mN Î + mN ĵ
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- A small rubber sphere has a mass of 3.64 g and a charge of -18.6 µC. It levitates, motionless, when placed in a uniform electric field perpendicular to the ground. What is the magnitude of the electric field (in N/C)? N/C What is the direction of the electric field? O upward O downward O east westThree charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 3.00 μC, and L 0.750 m.) 7.00 μ. 60.0⁰ 9 -4.00 uc (a) Calculate the electric field at the position of charge q due to the 7.00-μC and -4.00-μC charges. kN/CI+ KN/C J (b) Use your answer to part (a) to determine the force on charge q. mNi+ mNjthe diagram as shown. The charges of each marble are q₁6.50 μC, 9₂ 1.17 pc, and q3 -1.79 μC. Marble q, is a distance r = 3.00 cm to the left of the marble q₂, while marble q, is a distance r3 - 2.00 cm to the right of the marble q2, as shown. Calculate the magnitude of the electric field a distance = 1.00 cm to the left of the center marble. N/C 4 observation point 92 r₂ = 0m Another marble is placed 1 cm to the left of the middleimarble. If this new marble has a charge of 3.71 µC, calculate magnitude and direction of the force on it. 77. x magnitude
- Three charges are placed along the x-axis: q1 = 3.00 µC at X1 = -20.0 cm, q2 = -5.00 µC at x2 = 10.0 cm, and q3 = 6.00 µC at x3 = 25.00 cm. Determine the magnitude of the electric field at the origin. O 4 69x106 N/C O 2 96x106 N/C O 6 04x106 N/C O 4.31x106 N/CPlease AsapA uniformly charged ring of radius 10.0 cm has a total charge of 91.0 ?C. Find the electric field on the axis of the ring at the following distances from the center of the ring. (Choose the x-axis to point along the axis of the ring.) A) 1.00 cm -> î MN/C ? B) 5.00 cm -> î MN/C ? C) 30.0 cm -> î MN/C ? D) 100 cm-> î MN/C ?
- Please asapTwo identical thin rods of length L are each charged with a positive charge q that is uniformly distributed on each rod. The rods are arranged parallel to each other along the x direction and are separated by a distance 2d, as shown in the figure below. Determine the electric field at point P, which is located a distance d from the right endpoint of each rod. Hint: You will eventually need the following integral: น 1 S (a²+u²)3/2 du = − + C √a²+u²Three point-like charges are placed as shown in the figure, a = 20.0 cm and b = 66.0 cm. The charge (q) is placed halfway on the (b) side. Find the magnitude of the electric field at the top left corner. Let q1 = −2.00 μC, q2= −3.90 μC,and q3= −3.70 μC
- The point charges in the figure below are located at the corners of an equilateral triangle 20.0 cm on a side. (Assume that the +x-axis is to the right and the +y-axis is up along the page.) (a) Find the electric field (in N/C) at the location of qa in the figure, given that qb = +19.00 µC and qc = −8.00 µC. magnitude _______ N/C direction __________° counterclockwise from the +x-axis (b) What is the force (in N) on qa, given that qa = +2.50 nC? magnitude ______N direction _________° counterclockwise from the +x-axisIn the figure, the four particles are fixed in place and have charges q, = q2= 5e, q3 = 3e, and q4 = -12e (e = 1.6 × 10-19 C). Distance d= 5.0 µum. What is the magnitude of the net electric field at point P due to the particles? 4 Give your answer in N/C. (ke = /4ne, = 9.0 × 10° Nm²/C²)magnitude direction BµC 60.0⁰ A μC No 0.500 m i (a) Three point charges, A = 1.70 μC, B = 7.25 μC, and C = -4.60 µC, are located at the corners of an equilateral triangle as in the figure above. Find the magnitude and direction of the electric field at the position of the 1.70 μC charge. N/C ° below the +x-axis Cuc (b) How would the electric field at that point be affected if the charge there were doubled? The magnitude of the field would be halved. The field would be unchanged. The magnitude of the field would double. The magnitude of the field would quadruple. Would the magnitude of the electric force be affected? OYes