This time the sheet has charge density 5.38 x 10^-6 C, and your mass including the suit is 69.8 kg. How much charge must you give the suit if you want to fall down toward the sheet, but at the same rate as if you were on the Moon (remembering that the gravitational acceleration on the Moon is 1/6 what it is on Earth)? O 3.76E-03 C O 1.88E-03 C O 2.26E-03 C 2.82E-03 C

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Chapter1: Units, Trigonometry. And Vectors
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This problem involves calculating the required charge on a suit to fall toward a charged sheet with a specific charge density, mimicking the gravitational acceleration on the Moon.

**Problem Statement:**

This time the sheet has a charge density of \(5.38 \times 10^{-6} \, \text{C/m}^2\), and your mass, including the suit, is 69.8 kg. How much charge must you give the suit if you want to fall down toward the sheet at the same rate as if you were on the Moon? (Remember that the gravitational acceleration on the Moon is \(1/6\) what it is on Earth).

**Options:**

- \(3.76 \times 10^{-3} \, \text{C}\)
- \(1.88 \times 10^{-3} \, \text{C}\)
- \(2.26 \times 10^{-3} \, \text{C}\)
- \(2.82 \times 10^{-3} \, \text{C}\)

This scenario involves concepts of electrostatics and gravitation, requiring knowledge of charge density and gravitational acceleration conversion between Earth and the Moon. The goal is to find the correct charge from the given options.
Transcribed Image Text:This problem involves calculating the required charge on a suit to fall toward a charged sheet with a specific charge density, mimicking the gravitational acceleration on the Moon. **Problem Statement:** This time the sheet has a charge density of \(5.38 \times 10^{-6} \, \text{C/m}^2\), and your mass, including the suit, is 69.8 kg. How much charge must you give the suit if you want to fall down toward the sheet at the same rate as if you were on the Moon? (Remember that the gravitational acceleration on the Moon is \(1/6\) what it is on Earth). **Options:** - \(3.76 \times 10^{-3} \, \text{C}\) - \(1.88 \times 10^{-3} \, \text{C}\) - \(2.26 \times 10^{-3} \, \text{C}\) - \(2.82 \times 10^{-3} \, \text{C}\) This scenario involves concepts of electrostatics and gravitation, requiring knowledge of charge density and gravitational acceleration conversion between Earth and the Moon. The goal is to find the correct charge from the given options.
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