Cumulative [ edit]This table gives a probability that a statistic is less than Z (i.e. between negative infinity and Z).The values are calculated using the cumulative distribution function of a standard normal distribution with mean of zero and standard deviation of one, usually denotedwith the capital Greek letter (phi), is the integral(2) =P z/-(z) is related to the error function, or erf(z).(2) =+ erf+0.00+0.01+0.02+0.03+0.04+0.05+0.06+0.07+0.08+0.090.0 0.50000 0.50399 0.50798 0.51197 0,51595 0.51994 0.52392 0,52790 0.53188 0.535860.1 0.53983 0.54380 0.54776 0.55172 0.55567 0,55966 0.56360 0.56749 0.57142 0,575350.2 0.57926 0.58317 0.58706 0.59095 0.59483 0.59871 0.60257 0.60642 0.61026 0.614090.3 0.61791 0.62172 0.62552 0.62930 0.63307 0.63683 0.64058 0.64431 0.64803 0.651730.4 0.65542 0.65910 0.66276 0.66640 0.67003 0.67364 0.67724 0.68082 0.68439 0.687930.5 0.69146 0.497 0.69847 0.70194 0.70540 0.70884 0.71226 0.71566 0.71904 0.722400.6 0.725750.72907 0.73237 0.73565 0.73891 0.74215 0.74537 0.74857 0.75175 0.754900.7 0.75804 0.76115 0.76424 0.76730 0.77035 0.77337 0.77637 0.77935 0.78230 0.785240.8 0.78814 0.79103 0.79389 0.79673 0.79955 0.80234 0.80511 0.80785 0.81057 0.813270.9 0.81594 0.81859 0.82121 0.82381 0.82639 0.82894 0.83147 0.83398 0.83646 0.838911.0 0.84134 0.84375 0.84614 0.84849 0.85083 0.85314 0.85543 0.85769 0.85993 0.86214Station 1Station 2Station 3StationStation 1Station 2Station 3Average (Time)10 minutes25 minutes20 minutesStDev (Time)2 minutes5 minutes4 minutes (2) =%3D+0.00+0.01+0.02+0.03+0.04+0.05+0.06+0.07+0.08+0.090.0 0.50000 0.50399 0.50798 0.51197 0.51595 0.51994 0.52392 0.52790 0.53188 0.535860.1 0.53983 0.54380 0.54776 0.55172 0.55567 0.55966 0.56360 0.56749 0.57142 0.575350.2 0.57926 0.58317 0.58706 0.59095 0.59483 0.59871 0.60257 0.60642 0.61026 0.614090.3 0.61791 0.62172 0.62552 0.62930 0.63307 0.63683 0.64058 0.64431 0.64803 0.651730.4 0.65542 0.65910 0.66276 0.666400.67003 0.67364 0.67724 0.68082 0.68439 0.687930.5 0.69146 0.69497 0.69847 0.70194 0.70540 0.70884 0.71226 0.71566 0.71904 0.722400.6 0.72575 0.72907 0.73237 0.73565 0.73891 0.74215 0.74537 0.74857 0.75175 0.754900.7 0.75804 0.76115 0.76424 0.76730 0.77035 0.77337 0.77637 0.77935 0.78230 0.785240.8 0.78814 0.79103 0.79389 0.79673 0.79955 0.80234 0.80511 0.80785 0.81057 0.813270.9 0.81594 0.81859 0.82121 0.82381 0.82639 0.82894 0.83147 0.83398 0.83646 0.838911.0 0.84134 0.84375 0.84614 0.84849 0.85083 0.85314 0.85543 0.85769 0.85993 0.86214Station 1Station 2Station 3StationStation 1Station 2Station 3Average (Time)10 minutes25 minutes20 minutesStDev (Time)2 minutes5 minutes4 minutesShown above is a process with three stations. Units of flow must complete a station before proceeding to the next station. What is the probability that the process is completed in 55 minutesor less?O 0.000.07O 0.50O 0.931.0000000

From the given information, Station 1 2 3 Average 10 minutes 25 minutes 20 minutes…

This table gives a probability that a statistic is less than Z (i.e. between negative infinity and Z). The values are calculated using the cumulative distribution function of a standard normal distribution with mean of zero and standard deviation of one, usually denoted with the capital Greek letter (phi), is the integral IP z/ (z) is related to the error function, or erf(z). (2) = V27 -0-

This table gives a probability that a statistic is less than Z (i.e. between negative infinity and Z). The values are calculated using the cumulative distribution function of a standard normal distribution with mean of zero and standard deviation of one, usually denoted with the capital Greek letter (phi), is the integral IP z/ (z) is related to the error function, or erf(z). (2) = V27 -0-

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Concept explainers

Continuous Probability Distributions

Probability distributions are of two types, which are continuous probability distributions and discrete probability distributions. A continuous probability distribution contains an infinite number of values. For example, if time is infinite: you could count from 0 to a trillion seconds, billion seconds, so on indefinitely. A discrete probability distribution consists of only a countable set of possible values.

Normal Distribution

Suppose we had to design a bathroom weighing scale, how would we decide what should be the range of the weighing machine? Would we take the highest recorded human weight in history and use that as the upper limit for our weighing scale? This may not be a great idea as the sensitivity of the scale would get reduced if the range is too large. At the same time, if we keep the upper limit too low, it may not be usable for a large percentage of the population!

Question

Cumulative [ edit]
This table gives a probability that a statistic is less than Z (i.e. between negative infinity and Z).
The values are calculated using the cumulative distribution function of a standard normal distribution with mean of zero and standard deviation of one, usually denoted
with the capital Greek letter (phi), is the integral
(2) =
P z/-
(z) is related to the error function, or erf(z).
(2) =
+ erf
+0.00
+0.01
+0.02
+0.03
+0.04
+0.05
+0.06
+0.07
+0.08
+0.09
0.0 0.50000 0.50399 0.50798 0.51197 0,51595 0.51994 0.52392 0,52790 0.53188 0.53586
0.1 0.53983 0.54380 0.54776 0.55172 0.55567 0,55966 0.56360 0.56749 0.57142 0,57535
0.2 0.57926 0.58317 0.58706 0.59095 0.59483 0.59871 0.60257 0.60642 0.61026 0.61409
0.3 0.61791 0.62172 0.62552 0.62930 0.63307 0.63683 0.64058 0.64431 0.64803 0.65173
0.4 0.65542 0.65910 0.66276 0.66640 0.67003 0.67364 0.67724 0.68082 0.68439 0.68793
0.5 0.69146 0.
497 0.69847 0.70194 0.70540 0.70884 0.71226 0.71566 0.71904 0.72240
0.6 0.725750.72907 0.73237 0.73565 0.73891 0.74215 0.74537 0.74857 0.75175 0.75490
0.7 0.75804 0.76115 0.76424 0.76730 0.77035 0.77337 0.77637 0.77935 0.78230 0.78524
0.8 0.78814 0.79103 0.79389 0.79673 0.79955 0.80234 0.80511 0.80785 0.81057 0.81327
0.9 0.81594 0.81859 0.82121 0.82381 0.82639 0.82894 0.83147 0.83398 0.83646 0.83891
1.0 0.84134 0.84375 0.84614 0.84849 0.85083 0.85314 0.85543 0.85769 0.85993 0.86214
Station 1
Station 2
Station 3
Station
Station 1
Station 2
Station 3
Average (Time)
10 minutes
25 minutes
20 minutes
StDev (Time)
2 minutes
5 minutes
4 minutes

(2) =
%3D
+0.00
+0.01
+0.02
+0.03
+0.04
+0.05
+0.06
+0.07
+0.08
+0.09
0.0 0.50000 0.50399 0.50798 0.51197 0.51595 0.51994 0.52392 0.52790 0.53188 0.53586
0.1 0.53983 0.54380 0.54776 0.55172 0.55567 0.55966 0.56360 0.56749 0.57142 0.57535
0.2 0.57926 0.58317 0.58706 0.59095 0.59483 0.59871 0.60257 0.60642 0.61026 0.61409
0.3 0.61791 0.62172 0.62552 0.62930 0.63307 0.63683 0.64058 0.64431 0.64803 0.65173
0.4 0.65542 0.65910 0.66276 0.666400.67003 0.67364 0.67724 0.68082 0.68439 0.68793
0.5 0.69146 0.69497 0.69847 0.70194 0.70540 0.70884 0.71226 0.71566 0.71904 0.72240
0.6 0.72575 0.72907 0.73237 0.73565 0.73891 0.74215 0.74537 0.74857 0.75175 0.75490
0.7 0.75804 0.76115 0.76424 0.76730 0.77035 0.77337 0.77637 0.77935 0.78230 0.78524
0.8 0.78814 0.79103 0.79389 0.79673 0.79955 0.80234 0.80511 0.80785 0.81057 0.81327
0.9 0.81594 0.81859 0.82121 0.82381 0.82639 0.82894 0.83147 0.83398 0.83646 0.83891
1.0 0.84134 0.84375 0.84614 0.84849 0.85083 0.85314 0.85543 0.85769 0.85993 0.86214
Station 1
Station 2
Station 3
Station
Station 1
Station 2
Station 3
Average (Time)
10 minutes
25 minutes
20 minutes
StDev (Time)
2 minutes
5 minutes
4 minutes
Shown above is a process with three stations. Units of flow must complete a station before proceeding to the next station. What is the probability that the process is completed in 55 minutes
or less?
O 0.00
0.07
O 0.50
O 0.93
1.00
00000

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