This question will walk you through the process of calculating the number of atoms present in a sample of an element with a given mass. Consider a new smoke detector that contains 0.290 ug of americium-241. Step 3: Calculate the answer. The molar mass of americium-241 is 241.1 g/mol. A new smoke detector button contains 0.290 micrograms 241Am How many atoms 241Am 6.022 x 1023 atoms 241Am 9-00 0.290 いいこ STARTING AMOUNT 10-° ug 24*Am 6.022 x 10" atoms *"Am = 0.290 atoms 241Am 241 1g 241Am 1 ug 241Am ADD FACTOR DELETE ANSWER RESET (). 7.24 x 1020 0.290 1.16 x 10-16 0.001 9-01 1.20 x 10-9 1.75 x 1017 7.24 x 1017 000L 7.24 x 1014 1.
This question will walk you through the process of calculating the number of atoms present in a sample of an element with a given mass. Consider a new smoke detector that contains 0.290 ug of americium-241. Step 3: Calculate the answer. The molar mass of americium-241 is 241.1 g/mol. A new smoke detector button contains 0.290 micrograms 241Am How many atoms 241Am 6.022 x 1023 atoms 241Am 9-00 0.290 いいこ STARTING AMOUNT 10-° ug 24*Am 6.022 x 10" atoms *"Am = 0.290 atoms 241Am 241 1g 241Am 1 ug 241Am ADD FACTOR DELETE ANSWER RESET (). 7.24 x 1020 0.290 1.16 x 10-16 0.001 9-01 1.20 x 10-9 1.75 x 1017 7.24 x 1017 000L 7.24 x 1014 1.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question 14.e of 20
This question will walk you through the process of calculating the number of
atoms present in a sample of an element with a given mass. Consider a new
smoke detector that contains 0.290 µg of americium-241.
Step 3: Calculate the answer. The molar mass of americium-241 is 241.1 g/mol. A new
smoke detector button contains 0.290 micrograms . How many atoms 241Am
241 Am
6.022 x 1023
atoms 241Am
9-0
0.290
241.1
g 241Am
STARTING AMOUNT
241
1.
1.
10-6 ug 241Am
6.022 x 1023 atoms 241Am
1.1 g 241Am x
= 0.290 atoms 241Am
1g 241Am
1 ug 241Am
ADD FACTOR
DELETE
ANSWER
RESET
7.24 x 1020
0.290
1.16 x 10-16
0.001
9-0
6-0
90
1.20 x 10-9
1.75 x 1017
7.24 x 1017
7.24 x 1014
000
60
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