This question involves computing the greatest common factor between two positive integers and using greatest common factors to reduce fractions. You will write two methods in the NumberSystem class that follows. public class NumberSystem { /** Precondition: a and b are positive integers. *Returns the greatest common factor of a and b, as described in part (a). public static int gcf(int a, int b) { / to be implemented in part (a) */ } /** Precondition: numerator and denominator are positive integers. *Reduces the fraction numerator / denominator * and prints the result, as described in part (b). */ public static void reduceFraction(int numerator, int denominator) { / to be implemented in part (b) */ } } The greatest common factor (GCF) of two integers a and b is the largest integer that divides evenly into both a and b. For example, the GCF of 8 and 12 is 4. The greatest common factor can be computed using the following rules. Case I: If a is evenly divisible by b, then the GCF is b. Case II: If a is not evenly divisible by b, then the GCF of a and b is equal to the GCF of b and the remainder when a is divided by b. If the rule in case II is repeatedly applied, it is guaranteed to eventually result in case I. Consider the following examples. Example 1 In determining the GCF of 30 and 3, case I applies because 30 is evenly divisible by 3. Therefore, the GCF of 30 and 3 is 3. Example 2 In determining the GCF of 3 and 30, case Il applies because 3 is not evenly divisible by 30. The GCF of 3 and 30 will be equal to the GCF of 30 and the remainder when 3 is divided by 30, or 3. In determining the GCF of 30 and 3, case I applies because 30 is evenly divisible by 3. The GCF of 30 and 3 is 3, and therefore the GCF of 3 and 30 is also 3. Example 3 In determining the GCF of 24 and 9, case Il applies because 24 is not evenly divisible by 9. The GCF of 24 and 9 will be equal to the GCF of 9 and the remainder when 24 is divided by 9, or 6. In determining the GCF of 9 and 6, case Il applies because 9 is not evenly divisible by 6. The GCF of 9 and 6 will be equal to the GCF of 6 and the remainder when 9 is divided by 6, or 3. In determining the GCF of 6 and 3, case I applies because 6 is evenly divisible by 3. The GCF of 6 and 3 is 3, and therefore the GCF of 24 and 9 is also 3. Example 4 In determining the GCF of 7 and 3, case Il applies because 7 is not evenly divisible by 3. The GCF of 7 and 3 will be equal to the GCF of 3 and the remainder when 7 is divided by 3, or 1. In determining the GCF of 3 and 1, case I applies because 3 is evenly divisible by 1. The GCF of 3 and 1 is 1, and therefore the GCF of 7 and 3 is also 1. (a) The gcf method returns the greatest common factor of parameters a and b, as determined by case I and case II. Write the gcf method below. You are encouraged to implement this method recursively. /* Precondition: a and b are positive integers. * Returns the greatest common factor of a and b, as described in part (a). */ public static int gcf(int a, int b)