This question has several parts that must be completed sequentially. Derivation Look up the values of E° for the following half-cell reactions. Ag+ + e - Ag AgBr + e- - Ag + Br- Describe how you would use these values to determine the solubility product (Ksp) of AgBr at 25.0°C. Step 1 of 4 Recall and write the equilibrium expression for the Ksp of AgBr. (Subscripts and superscripts that include letters must be enclosed in braces {}.) chemPad O Help Greek k_sp=[Ag*][Br] k_sp=[Ag^+][Br^-] Your answer contains an improperly or incompletely formatted chemical formula. Your answer contains improper superscript or subscript formatting.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Standard Electrode Potentials
half-reaction
E° (V)
half-reaction
E° (V)
Hg²*(aq) + 2 e¯ → Hg(1)
ClO"(aq) + H20(1) + 2 e¯ → Cl¯(aq) + 2 OH¯(aq)
Ag°(aq) + e¯ → Ag(s)
Hg2*(aq) + 2 e → 2 Hg(1)
Fe**(aq) + e¯ → Fe²*(aq)
2 NO(g) + H20(1) + 2 e¯ → N20(g) + 2 OH¯(aq)
02(g) + 2 H*(aq) + 2 e¯→ H202(aq)
F2(g) + 2 е — 2F (aq)
03(g) + 2 H*(aq) + 2 e¯ → 02(g) + H20(1)
+2.87
->
+0.851
+2.076
+0.841
Со (ag) + e —
► Co²*
*(aq)
+1.92
+0.800
Н.0-(аq) + 2 H'(aq) + 2 е' > 2 Н,0()
+1.776
+0.797
Ce*(aq) + e¯ → Ce*(aq)
PbO2(s) + SO, (aq) + 4 H* (aq) + 2 e
MnO4¯(aq) + 4 H*(aq) + 3 e¯ → MnO2(s) + 2 H20(1)
2 HCIO(aq) + 2 H*(aq) + 2 e¯ →
2 NO(g) + 2 H*(aq) + 2 e¯ → N20(g) + H20(1)
Mn*(aq) + e¯ → Mn²*(aq)
Mn04 (aq) + 8 Hн"(аq) + 5 е —
Au**(aq) + 3 e¯ → Au(s)
HCIO (aq) + H"(aq) + 2 e — СГ (аq) + H,0()
2 ClO3¯(aq) + 12 H*(aq) + 10 e¯
PbO2(s) + 4 H*(aq) + 2 e¯ →
Cl2(g) + 2 e¯ → 2 Cl¯(aq)
HCrO4¯(aq) + 7 H*(aq) + 3 e¯ → Cr*(aq) + 4 H20(1)
2 HNO2(aq) + 4 H*(aq) + 4 e¯ → N,0(g) + 3 H,0(1)
TI³*(aq) + 2 e¯ → TI*(aq)
Cr,0, (aq) + 14 H*(aq) + 6 e¯ → 2 Cr* (aq) + 7 H20(1)
02(g) + 4 H*(aq) + 4 e¯ → 2 H20(1)
Mn02(s) + 4 H*(aq) + 2 e¯ →
ClO, (aq) + 3 H*(aq) + 2 e¯ → HC1O2(aq) + H20(1)
ClO, (aq) + 2 H*(aq) + 2 e¯ → Cl03 (aq) + H20(1)
CIО3 (аq) + 2 Н"(ад) + е —>
+1.72
+0.771
PBSO4(s) + 2 H20(1)
+1.691
+0.760
+1.679
+0.695
Cl2(g) + 2 H20(1)
+1.611
ClO3 (aq) + 3 H,0(1) + 6 e¯ → Cl¯(aq) + 6 OH¯(aq)
MnO4¯(aq) + 2 H20(1) + 3 e
S-06 (aq) + 4 H"(аq) + 2 е — 2 H-SO;(aq)
I3 (aq) + 2 e¯ → 3 I (aq)
1,(s) + 2 е — 2 (aq)
+0.620
+1.591
MnO2(s) + 4 OH (aq)
+0.595
+1.54
+0.564
Mn²*(aq) + 4 H20(1)
+0.536
+1.507
+1.498
+0.536
Cu'(aq) + e¯
→ Cu(s)
02(g) + 2 H20(1) + 4 e¯ → 4 OH¯(aq)
+1.482
+0.521
> Cl2(g) + 6 H20(l)
Pb²*(aq) + 2 H20(1)
+1.470
+0.401
Fe(CN),“(aq) + e → Fe(CN),*(aq)
ClO, (aq) + H20(1) + 2 e¯ →
Cu²*(aq) + 2 e¯ → Cu(s)
Hg,Cl,(s) + 2 e¯ → 2 Hg(1) + 2 CI¯(aq)
PbO2(s) + H20(1) + 2 e¯ → Pb0(s) + 2 OH¯(aq)
AgCl(s) + e¯ → Ag(s) + Cl¯(aq)
so,² (aq) + 4 H*(aq) + 2 e¯ → H2SO3(aq) + H20(1)
Cu*(aq) + e¯ → Cu°(aq)
Sn**(aq) + 2 e¯ → Sn²*(aq)
2 NO2 (aq) + 3 H20(1) + 4 e¯ → N20(g) + 6 OH¯(aq)
S,0, (aq) + 2 e → 2 S,03² (aq)
AgBr(s) + e¯ → Ag(s) + Br¯(aq)
NO3 (aq) + H20(1) + 2 e
2 H*(aq) + 2 e¯ → H2(g)
+1.455
+0.36
+1.36
— СIО3 (аq) + 2 он (аq)
+0.360
+1.350
+0.342
+1.297
+0.268
+1.252
+0.247
+1.23
+0.222
+1.229
+0.172
Mn²*(aq) + 2 H20(1)
+1.224
+0.153
+1.214
+0.151
+1.189
+0.150
ClO2(g) + H20(1)
+1.152
+0.080
Br2(aq) + 2 e → 2 Br¯(aq)
Br2(1) + 2 e → 2 Br¯(aq)
N204(g) + 2 H*(aq) + 2 e¯ →
+1.087
+0.0713
+1.066
NO2 (aq) + 2 OH¯(aq)
+0.010
2 ΗΝΟ, (ag)
N204(g) + 4 H*(aq) + 4 e¯ → 2 NO(g) + 2 H20(1)
NO(g) + H20(1)
→ NO(g) + 2 H20(1)
+1.065
+1.035
+ H*(aq) + e –→
HNO2(aq)
NO3 (aq) + 4 H"(аq) + 3 е
2 Hg**(aq) + 2 e¯ → Hg,*(aq)
N204(g) + 2 e¯ →
+0.983
+0.957
+0.92
2 NO, (aq)
+0.867
Transcribed Image Text:Standard Electrode Potentials half-reaction E° (V) half-reaction E° (V) Hg²*(aq) + 2 e¯ → Hg(1) ClO"(aq) + H20(1) + 2 e¯ → Cl¯(aq) + 2 OH¯(aq) Ag°(aq) + e¯ → Ag(s) Hg2*(aq) + 2 e → 2 Hg(1) Fe**(aq) + e¯ → Fe²*(aq) 2 NO(g) + H20(1) + 2 e¯ → N20(g) + 2 OH¯(aq) 02(g) + 2 H*(aq) + 2 e¯→ H202(aq) F2(g) + 2 е — 2F (aq) 03(g) + 2 H*(aq) + 2 e¯ → 02(g) + H20(1) +2.87 -> +0.851 +2.076 +0.841 Со (ag) + e — ► Co²* *(aq) +1.92 +0.800 Н.0-(аq) + 2 H'(aq) + 2 е' > 2 Н,0() +1.776 +0.797 Ce*(aq) + e¯ → Ce*(aq) PbO2(s) + SO, (aq) + 4 H* (aq) + 2 e MnO4¯(aq) + 4 H*(aq) + 3 e¯ → MnO2(s) + 2 H20(1) 2 HCIO(aq) + 2 H*(aq) + 2 e¯ → 2 NO(g) + 2 H*(aq) + 2 e¯ → N20(g) + H20(1) Mn*(aq) + e¯ → Mn²*(aq) Mn04 (aq) + 8 Hн"(аq) + 5 е — Au**(aq) + 3 e¯ → Au(s) HCIO (aq) + H"(aq) + 2 e — СГ (аq) + H,0() 2 ClO3¯(aq) + 12 H*(aq) + 10 e¯ PbO2(s) + 4 H*(aq) + 2 e¯ → Cl2(g) + 2 e¯ → 2 Cl¯(aq) HCrO4¯(aq) + 7 H*(aq) + 3 e¯ → Cr*(aq) + 4 H20(1) 2 HNO2(aq) + 4 H*(aq) + 4 e¯ → N,0(g) + 3 H,0(1) TI³*(aq) + 2 e¯ → TI*(aq) Cr,0, (aq) + 14 H*(aq) + 6 e¯ → 2 Cr* (aq) + 7 H20(1) 02(g) + 4 H*(aq) + 4 e¯ → 2 H20(1) Mn02(s) + 4 H*(aq) + 2 e¯ → ClO, (aq) + 3 H*(aq) + 2 e¯ → HC1O2(aq) + H20(1) ClO, (aq) + 2 H*(aq) + 2 e¯ → Cl03 (aq) + H20(1) CIО3 (аq) + 2 Н"(ад) + е —> +1.72 +0.771 PBSO4(s) + 2 H20(1) +1.691 +0.760 +1.679 +0.695 Cl2(g) + 2 H20(1) +1.611 ClO3 (aq) + 3 H,0(1) + 6 e¯ → Cl¯(aq) + 6 OH¯(aq) MnO4¯(aq) + 2 H20(1) + 3 e S-06 (aq) + 4 H"(аq) + 2 е — 2 H-SO;(aq) I3 (aq) + 2 e¯ → 3 I (aq) 1,(s) + 2 е — 2 (aq) +0.620 +1.591 MnO2(s) + 4 OH (aq) +0.595 +1.54 +0.564 Mn²*(aq) + 4 H20(1) +0.536 +1.507 +1.498 +0.536 Cu'(aq) + e¯ → Cu(s) 02(g) + 2 H20(1) + 4 e¯ → 4 OH¯(aq) +1.482 +0.521 > Cl2(g) + 6 H20(l) Pb²*(aq) + 2 H20(1) +1.470 +0.401 Fe(CN),“(aq) + e → Fe(CN),*(aq) ClO, (aq) + H20(1) + 2 e¯ → Cu²*(aq) + 2 e¯ → Cu(s) Hg,Cl,(s) + 2 e¯ → 2 Hg(1) + 2 CI¯(aq) PbO2(s) + H20(1) + 2 e¯ → Pb0(s) + 2 OH¯(aq) AgCl(s) + e¯ → Ag(s) + Cl¯(aq) so,² (aq) + 4 H*(aq) + 2 e¯ → H2SO3(aq) + H20(1) Cu*(aq) + e¯ → Cu°(aq) Sn**(aq) + 2 e¯ → Sn²*(aq) 2 NO2 (aq) + 3 H20(1) + 4 e¯ → N20(g) + 6 OH¯(aq) S,0, (aq) + 2 e → 2 S,03² (aq) AgBr(s) + e¯ → Ag(s) + Br¯(aq) NO3 (aq) + H20(1) + 2 e 2 H*(aq) + 2 e¯ → H2(g) +1.455 +0.36 +1.36 — СIО3 (аq) + 2 он (аq) +0.360 +1.350 +0.342 +1.297 +0.268 +1.252 +0.247 +1.23 +0.222 +1.229 +0.172 Mn²*(aq) + 2 H20(1) +1.224 +0.153 +1.214 +0.151 +1.189 +0.150 ClO2(g) + H20(1) +1.152 +0.080 Br2(aq) + 2 e → 2 Br¯(aq) Br2(1) + 2 e → 2 Br¯(aq) N204(g) + 2 H*(aq) + 2 e¯ → +1.087 +0.0713 +1.066 NO2 (aq) + 2 OH¯(aq) +0.010 2 ΗΝΟ, (ag) N204(g) + 4 H*(aq) + 4 e¯ → 2 NO(g) + 2 H20(1) NO(g) + H20(1) → NO(g) + 2 H20(1) +1.065 +1.035 + H*(aq) + e –→ HNO2(aq) NO3 (aq) + 4 H"(аq) + 3 е 2 Hg**(aq) + 2 e¯ → Hg,*(aq) N204(g) + 2 e¯ → +0.983 +0.957 +0.92 2 NO, (aq) +0.867
This question has several parts that must be completed sequentially.
Derivation
Look up the values of E0 for the following half-cell reactions.
Ag+ + e -
Ag
AgBr + e- - Ag + Br-
Describe how you would use these values to determine the solubility product (Ksp) of AgBr at 25.0°C.
Step 1 of 4
Recall and write the equilibrium expression for the Ksp of AgBr. (Subscripts and superscripts that include letters must be enclosed in braces {}.)
chemPad
Help
Greek -
k_sp=[Ag+][Br]
k_sp=[Ag^+][Br^-]
Your answer contains an improperly or incompletely formatted chemical formula. Your answer contains improper superscript or subscript formatting.
Transcribed Image Text:This question has several parts that must be completed sequentially. Derivation Look up the values of E0 for the following half-cell reactions. Ag+ + e - Ag AgBr + e- - Ag + Br- Describe how you would use these values to determine the solubility product (Ksp) of AgBr at 25.0°C. Step 1 of 4 Recall and write the equilibrium expression for the Ksp of AgBr. (Subscripts and superscripts that include letters must be enclosed in braces {}.) chemPad Help Greek - k_sp=[Ag+][Br] k_sp=[Ag^+][Br^-] Your answer contains an improperly or incompletely formatted chemical formula. Your answer contains improper superscript or subscript formatting.
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