This question has several parts that must be completed sequentially. Derivation Look up the values of E° for the following half-cell reactions. Ag+ + e - Ag AgBr + e- - Ag + Br- Describe how you would use these values to determine the solubility product (Ksp) of AgBr at 25.0°C. Step 1 of 4 Recall and write the equilibrium expression for the Ksp of AgBr. (Subscripts and superscripts that include letters must be enclosed in braces {}.) chemPad O Help Greek k_sp=[Ag*][Br] k_sp=[Ag^+][Br^-] Your answer contains an improperly or incompletely formatted chemical formula. Your answer contains improper superscript or subscript formatting.
This question has several parts that must be completed sequentially. Derivation Look up the values of E° for the following half-cell reactions. Ag+ + e - Ag AgBr + e- - Ag + Br- Describe how you would use these values to determine the solubility product (Ksp) of AgBr at 25.0°C. Step 1 of 4 Recall and write the equilibrium expression for the Ksp of AgBr. (Subscripts and superscripts that include letters must be enclosed in braces {}.) chemPad O Help Greek k_sp=[Ag*][Br] k_sp=[Ag^+][Br^-] Your answer contains an improperly or incompletely formatted chemical formula. Your answer contains improper superscript or subscript formatting.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Standard Electrode Potentials
half-reaction
E° (V)
half-reaction
E° (V)
Hg²*(aq) + 2 e¯ → Hg(1)
ClO"(aq) + H20(1) + 2 e¯ → Cl¯(aq) + 2 OH¯(aq)
Ag°(aq) + e¯ → Ag(s)
Hg2*(aq) + 2 e → 2 Hg(1)
Fe**(aq) + e¯ → Fe²*(aq)
2 NO(g) + H20(1) + 2 e¯ → N20(g) + 2 OH¯(aq)
02(g) + 2 H*(aq) + 2 e¯→ H202(aq)
F2(g) + 2 е — 2F (aq)
03(g) + 2 H*(aq) + 2 e¯ → 02(g) + H20(1)
+2.87
->
+0.851
+2.076
+0.841
Со (ag) + e —
► Co²*
*(aq)
+1.92
+0.800
Н.0-(аq) + 2 H'(aq) + 2 е' > 2 Н,0()
+1.776
+0.797
Ce*(aq) + e¯ → Ce*(aq)
PbO2(s) + SO, (aq) + 4 H* (aq) + 2 e
MnO4¯(aq) + 4 H*(aq) + 3 e¯ → MnO2(s) + 2 H20(1)
2 HCIO(aq) + 2 H*(aq) + 2 e¯ →
2 NO(g) + 2 H*(aq) + 2 e¯ → N20(g) + H20(1)
Mn*(aq) + e¯ → Mn²*(aq)
Mn04 (aq) + 8 Hн"(аq) + 5 е —
Au**(aq) + 3 e¯ → Au(s)
HCIO (aq) + H"(aq) + 2 e — СГ (аq) + H,0()
2 ClO3¯(aq) + 12 H*(aq) + 10 e¯
PbO2(s) + 4 H*(aq) + 2 e¯ →
Cl2(g) + 2 e¯ → 2 Cl¯(aq)
HCrO4¯(aq) + 7 H*(aq) + 3 e¯ → Cr*(aq) + 4 H20(1)
2 HNO2(aq) + 4 H*(aq) + 4 e¯ → N,0(g) + 3 H,0(1)
TI³*(aq) + 2 e¯ → TI*(aq)
Cr,0, (aq) + 14 H*(aq) + 6 e¯ → 2 Cr* (aq) + 7 H20(1)
02(g) + 4 H*(aq) + 4 e¯ → 2 H20(1)
Mn02(s) + 4 H*(aq) + 2 e¯ →
ClO, (aq) + 3 H*(aq) + 2 e¯ → HC1O2(aq) + H20(1)
ClO, (aq) + 2 H*(aq) + 2 e¯ → Cl03 (aq) + H20(1)
CIО3 (аq) + 2 Н"(ад) + е —>
+1.72
+0.771
PBSO4(s) + 2 H20(1)
+1.691
+0.760
+1.679
+0.695
Cl2(g) + 2 H20(1)
+1.611
ClO3 (aq) + 3 H,0(1) + 6 e¯ → Cl¯(aq) + 6 OH¯(aq)
MnO4¯(aq) + 2 H20(1) + 3 e
S-06 (aq) + 4 H"(аq) + 2 е — 2 H-SO;(aq)
I3 (aq) + 2 e¯ → 3 I (aq)
1,(s) + 2 е — 2 (aq)
+0.620
+1.591
MnO2(s) + 4 OH (aq)
+0.595
+1.54
+0.564
Mn²*(aq) + 4 H20(1)
+0.536
+1.507
+1.498
+0.536
Cu'(aq) + e¯
→ Cu(s)
02(g) + 2 H20(1) + 4 e¯ → 4 OH¯(aq)
+1.482
+0.521
> Cl2(g) + 6 H20(l)
Pb²*(aq) + 2 H20(1)
+1.470
+0.401
Fe(CN),“(aq) + e → Fe(CN),*(aq)
ClO, (aq) + H20(1) + 2 e¯ →
Cu²*(aq) + 2 e¯ → Cu(s)
Hg,Cl,(s) + 2 e¯ → 2 Hg(1) + 2 CI¯(aq)
PbO2(s) + H20(1) + 2 e¯ → Pb0(s) + 2 OH¯(aq)
AgCl(s) + e¯ → Ag(s) + Cl¯(aq)
so,² (aq) + 4 H*(aq) + 2 e¯ → H2SO3(aq) + H20(1)
Cu*(aq) + e¯ → Cu°(aq)
Sn**(aq) + 2 e¯ → Sn²*(aq)
2 NO2 (aq) + 3 H20(1) + 4 e¯ → N20(g) + 6 OH¯(aq)
S,0, (aq) + 2 e → 2 S,03² (aq)
AgBr(s) + e¯ → Ag(s) + Br¯(aq)
NO3 (aq) + H20(1) + 2 e
2 H*(aq) + 2 e¯ → H2(g)
+1.455
+0.36
+1.36
— СIО3 (аq) + 2 он (аq)
+0.360
+1.350
+0.342
+1.297
+0.268
+1.252
+0.247
+1.23
+0.222
+1.229
+0.172
Mn²*(aq) + 2 H20(1)
+1.224
+0.153
+1.214
+0.151
+1.189
+0.150
ClO2(g) + H20(1)
+1.152
+0.080
Br2(aq) + 2 e → 2 Br¯(aq)
Br2(1) + 2 e → 2 Br¯(aq)
N204(g) + 2 H*(aq) + 2 e¯ →
+1.087
+0.0713
+1.066
NO2 (aq) + 2 OH¯(aq)
+0.010
2 ΗΝΟ, (ag)
N204(g) + 4 H*(aq) + 4 e¯ → 2 NO(g) + 2 H20(1)
NO(g) + H20(1)
→ NO(g) + 2 H20(1)
+1.065
+1.035
+ H*(aq) + e –→
HNO2(aq)
NO3 (aq) + 4 H"(аq) + 3 е
2 Hg**(aq) + 2 e¯ → Hg,*(aq)
N204(g) + 2 e¯ →
+0.983
+0.957
+0.92
2 NO, (aq)
+0.867
![This question has several parts that must be completed sequentially.
Derivation
Look up the values of E0 for the following half-cell reactions.
Ag+ + e -
Ag
AgBr + e- - Ag + Br-
Describe how you would use these values to determine the solubility product (Ksp) of AgBr at 25.0°C.
Step 1 of 4
Recall and write the equilibrium expression for the Ksp of AgBr. (Subscripts and superscripts that include letters must be enclosed in braces {}.)
chemPad
Help
Greek -
k_sp=[Ag+][Br]
k_sp=[Ag^+][Br^-]
Your answer contains an improperly or incompletely formatted chemical formula. Your answer contains improper superscript or subscript formatting.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F14e51fbd-8bc7-4604-ba1b-5c934c5c4cfb%2F019a0eb6-8065-47a6-8ced-92bb9862e552%2Fg3bforp_processed.png&w=3840&q=75)
Transcribed Image Text:This question has several parts that must be completed sequentially.
Derivation
Look up the values of E0 for the following half-cell reactions.
Ag+ + e -
Ag
AgBr + e- - Ag + Br-
Describe how you would use these values to determine the solubility product (Ksp) of AgBr at 25.0°C.
Step 1 of 4
Recall and write the equilibrium expression for the Ksp of AgBr. (Subscripts and superscripts that include letters must be enclosed in braces {}.)
chemPad
Help
Greek -
k_sp=[Ag+][Br]
k_sp=[Ag^+][Br^-]
Your answer contains an improperly or incompletely formatted chemical formula. Your answer contains improper superscript or subscript formatting.
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