This problem illustrates that the factor of safety for a machine element depends on the particular point selected for analysis. Here you are to compute factors of safety, based upon the distortion-energy theory, for stress elements at A and B of the member shown in the figure. This bar is made of AISI 1006 cold-drawn steel and is loaded by the forces F= 0.55 kN, P = 4 kN, and T= 25 N-m. Given: Sy= 280 MPa. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. B 15-mm D. -100 mm

This problem illustrates that the factor of safety for a machine element depends on the particular point selected for analysis. Here you are to compute factors of safety, based upon the distortion-energy theory, for stress elements at A and B of the member shown in the figure. This bar is made of AISI 1006 cold-drawn steel and is loaded by the forces F= 0.55 kN, P = 4 kN, and T= 25 N-m. Given: Sy= 280 MPa. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. B 15-mm D. -100 mm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A cylindrical 1045 steel bar (see the figure below) is subjected to repeated compression- tension stress cycling along its axis. If the load amplitude is 23,000 N, calculate the minimum allowable bar diameter (in mm) to ensure that fatigue failure will not occur. Assume a factor of safety of 2.0. Maximum stress, S (MPa) 700 600 500 400 300 200 100 0 4340 steel 104 Ti-5Al-2.5Sn titanium alloy 70Cu-30Zn brass EQ21A-T6 Mg alloy 105 1045 steel Ductile cast iron 107 2014-T6 Al alloy 108 10⁹ 106 Cycles to failure, N Data taken from the following sources and reproduced with permission of ASM International, Materials Park, OH, 44073: ASM Handbook, Vol. I, Properties and Selection: Irons, Steels, and High-Performance Alloys, 1990; ASM Handbook, Vol. 2, Properties and Selection; Nonferrous Alloys and Special- Purpose Materials, 1990; G. M. Sinclair and W. J. Craig, "Influence of Grain Size on Work Hardening and Fatigue Characteristics of Alpha Brass," Transactions of ASM, Vol. 44, 1952.
The stepped and surface-ground steel bar in the figure is subjected to a bending moment varying between Mz=100 Nm and Mz=250 Nm and a torsional moment varying between Tx=80 Nm and Tx=320 Nm in opposite directions. The tensile strength of the rod material is Sut=800 MPa and it works under room conditions. For 50 percent reliability, check the fatigue safety of the rod.
can you solve (a) and (c) using mohrs circle
The shaft shown the figure below, is supported by a bearing on the left end. The shaft also supports a pulley on the right end, which rotates. The tensions in the belt of the pulley are F. =2,739 y and F,=1,362 N. Also, a completely reversed axial load of F 11 N is applied to the right end. The shaft is made of UNS G10450 CD steel, with 2. a ground surface and 99 z reliability and operates at room temperature. Assume, K =1.35 for torque and formula 6- 34 to calculate K fs' K, - 1 K = 1 + (6-34) 1+ va/ Vr Bending or axial: Va = 0.246 – 3.08(10)S+ 1.51(10-)S, – 2.67(10-*)S 50 s Su s 250 kpsi Va = 1.24 - 2.25(10-)S+1.60(10)$ – 4.11(10-1)S, 340 S S 1700 MPa (6-35) Torsion: Va = 0.190 – 2.51(10-)S+ 1.35(10-), – 2.67(10-)S 50 < Su < 220 kpsi Va = 0.958 – 1.83(10-)S+ 1.43(10-")S-4.11(10-1)s 340 < S S 1500 MPa (6-36) All fillet radius r-0.1d All dimensions are in mm 300D -30 100 :600 1. Identify the critical point(s) on the shaft and show it clearly on the diagram. 2. Draw the cartesian…
A solid round bar with diameter of 2 in has a groove cut to a diameter of 1.8 in, with a radius of 0.1 in. The bar is not rotating. The bar is loaded with a repeated bending load that causes the bending moment at the groove to fluctuate between 0 and 25 000 lbf in. The bar is hot-rolled AISI 1095, but the groove has been machined. Determine the factor of safety for fatigue based on infinite life and the factor of safety for yielding. Plars & .
Don't copy from any source and don't give handwritten solution
Answer is Not 43,-1 and 22.
Solve please
Tassimo mikanikium
Answer is closer to 32 kN/m, but how does it get there?
Find the correct solution for the given question,ASAP