This problem has you write a nested loop to process a list of list of int, and accumulate a list of list of int. The starter code provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains only even ints. You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist. You'll need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator. 1 def only_evens (1st: list[1ist[int]]) -> 1list[list[int]]: """Return a list of the lists in 1st that contain only even integers. 3 >>> only_evens ([[1, 2, 4], [4, e, 6], [22, 4, 3], [2]]) [[4, 0, 6], [2]] 4 7. even_lists = [] 8 10 for sublist in 1st:

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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This problem has you write a nested loop to process a list of list of int, and accumulate a list of list of int. The starter code
provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains only
even ints.
You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist. You'll
need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator.
1 def only_evens (1st: list[list[int]]) -> list[list[int]]:
"""Return a list of the lists in 1st that contain only even integers.
4
>>> only_evens ([[1, 2, 4], [4, 0, 6], [22, 4, 3], [2]])
[[4, 0, 6], [2]]
6.
8.
even_lists =
[]
10
for sublist in 1st:
11
12
# write your code here (please read above for a suggested approach)
13
14
return even_lists
Transcribed Image Text:This problem has you write a nested loop to process a list of list of int, and accumulate a list of list of int. The starter code provides an accumulator for the result and a loop over the lists, and you need to write the code that checks whether sublist contains only even ints. You'll probably want a one-way flag: a Boolean variable that starts out as True and is set to False if you find an odd int in the sublist. You'll need to check the value of this variable to figure out whether to append sublist to the even_lists accumulator. 1 def only_evens (1st: list[list[int]]) -> list[list[int]]: """Return a list of the lists in 1st that contain only even integers. 4 >>> only_evens ([[1, 2, 4], [4, 0, 6], [22, 4, 3], [2]]) [[4, 0, 6], [2]] 6. 8. even_lists = [] 10 for sublist in 1st: 11 12 # write your code here (please read above for a suggested approach) 13 14 return even_lists
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