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This is CSTR. Reactant : A Conc. of input : C_Ai [g/L] Conc. of output : C_A [g/L] q = 20 [L/s] Volume of the reactor, V = 40 [L] The reaction is 2nd-order ; dC_A/dt = -k(C_A)^2.  (k : constant) Q) When step input is 6, find C_A(t). (k = 5/4 [L/gs], C_A,s = 1 [g/L])

This is CSTR. Reactant : A Conc. of input : C_Ai [g/L] Conc. of output : C_A [g/L] q = 20 [L/s] Volume of the reactor, V = 40 [L] The reaction is 2nd-order ; dC_A/dt = -k(C_A)^2.  (k : constant) Q) When step input is 6, find C_A(t). (k = 5/4 [L/gs], C_A,s = 1 [g/L])

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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This is CSTR.

Reactant : A

Conc. of input : C_Ai [g/L]

Conc. of output : C_A [g/L]

q = 20 [L/s]

Volume of the reactor, V = 40 [L]

The reaction is 2nd-order ; dC_A/dt = -k(C_A)^2.  (k : constant)

Q) When step input is 6, find C_A(t). (k = 5/4 [L/gs], C_A,s = 1 [g/L])

CAi V CA
Transcribed Image Text:CAi V CA
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