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5.) 10) The liquid-phase reaction A→B+C was carried out in a batch reactor initially charged with 5 mol/L species A. The graph below contains linearized data from the reaction. Determine the reaction order and specific reaction rate constant and write out the full rate law. Note: you must have correct units (mol, L, min) for full credit. 4 Batch reactor Inf-dC,₁/dt) 0 2 1 y = 2.2849x - 1.2542 R2 = 0.9999 In (CA) 2

5.) 10) The liquid-phase reaction A→B+C was carried out in a batch reactor initially charged with 5 mol/L species A. The graph below contains linearized data from the reaction. Determine the reaction order and specific reaction rate constant and write out the full rate law. Note: you must have correct units (mol, L, min) for full credit. 4 Batch reactor Inf-dC,₁/dt) 0 2 1 y = 2.2849x - 1.2542 R2 = 0.9999 In (CA) 2

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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5.) 10) The liquid-phase reaction A→B+C was carried out in a batch reactor initially charged with 5 mol/L species A. The graph below contains linearized data from the reaction. Determine the reaction order and specific reaction rate constant and write out the full rate law. Note: you must have correct units (mol, L, min) for full credit. 4 Batch reactor Inf-dC,₁/dt) 0 2 1 y = 2.2849x - 1.2542 R2 = 0.9999 In (CA) 2
Transcribed Image Text:5.) 10) The liquid-phase reaction A→B+C was carried out in a batch reactor initially charged with 5 mol/L species A. The graph below contains linearized data from the reaction. Determine the reaction order and specific reaction rate constant and write out the full rate law. Note: you must have correct units (mol, L, min) for full credit. 4 Batch reactor Inf-dC,₁/dt) 0 2 1 y = 2.2849x - 1.2542 R2 = 0.9999 In (CA) 2
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