A liquid phase reaction A→ 2.5 was done in a 100 L isothermal CSTR. Initially, the reactor is charged with 1.75 mM of pure reactant A at a rate of 2.0 L min-¹. The said reaction follows the rate law: -TA = KC 1.25 Where CA is the concentration of reactant A, and k is the reaction constant. The reaction constant varies with temperature according to the following Arrhenius type relationship: k L0.25 mol0.25min -1525 = 1000e T What will be the steady-state concentration of A and B if the reactor is operated T=325 K2
A liquid phase reaction A→ 2.5 was done in a 100 L isothermal CSTR. Initially, the reactor is charged with 1.75 mM of pure reactant A at a rate of 2.0 L min-¹. The said reaction follows the rate law: -TA = KC 1.25 Where CA is the concentration of reactant A, and k is the reaction constant. The reaction constant varies with temperature according to the following Arrhenius type relationship: k L0.25 mol0.25min -1525 = 1000e T What will be the steady-state concentration of A and B if the reactor is operated T=325 K2
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:A liquid phase reaction A- → 2.5 was done in a 100 L isothermal CSTR. Initially, the
reactor is charged with 1.75 mM of pure reactant A at a rate of 2.0 L min-¹. The said
reaction follows the rate law:
-TA = KCA
Where CA is the concentration of reactant A, and k is the reaction constant. The
reaction constant varies with temperature according to the following Arrhenius type
relationship:
k
L⁰.25
mol0.25 min
1.25
=
1000e
-1525
What will be the steady-state concentration of A and B if the reactor is operated
T=325 K?
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