This interval of values of the test statistics where the null hypothesis will not be accepted. a.Acceptance region b.Rejection region c.Significance level d.Critical value
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- The table below summarizes data from a survey of a sample of women. Using a 0.01 significance level, and assuming that the sample sizes of 900 men and 300 women are predetermined, test the claim that the proportions of agree/disagree responses are the same for subjects interviewed by men and the subjects interviewed by women. Does it appear that the gender of the interviewer affected the responses of women? what is the test static? what is the critical value? what is th P-value? Gender of Interviewer Man Woman Women who agree 572 243 Women who disagree 328 57 Chi-square Degrees of Freedom 0.995 0.99 0.975 0.95 0.90 0.10 0.05 0.025 0.01 0.005 1 - - 0.001 0.004 0.016 2.706 3.841 5.024 6.635 7.879 2 0.010 0.020 0.051 0.103 0.211 4.605 5.991 7.378 9.210 10.597 3 0.072 0.115 0.216 0.352 0.584 6.251 7.815 9.348 11.345…You wish to test the following claim (Ha) at a significance level of a = 0.001. H,:P = P2 Ha:pi > p You obtain 303 successes in a sample of size n = 488 from the first population. You obtain 159 successes in a sample of size ry = 266 from the second population. What is the test statistic for this sample? test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the first population proportion is greater than the second population proportion. O There is not sufficient evidence to warrant rejection of the claim that the first population proportion is greater than the second population proportion. O The sample data support the claim that the first population…A study is designed to determine the effect of an office-training course on typing productivity. Fifteen typists who have not taken the course are randomly selected. The investigator assigns 20 pages of equally difficult text to be typed by each typist both before and after completing the training course. The investigator wants to find out whether the training course has reduced the number of errors by more than 10. Define d = Before − After. Significance level What conclusion should we reach if the p-value is 0.113?
- The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 4.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. LOADING... Click the icon to view the display from technology. Question content area bottom Part 1 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. H0: μ=4.00 Mbps H1: μ>4.00 Mbps B. H0: μ<4.00 Mbps H1: μ=4.00 Mbps C. H0: μ=4.00 Mbps H1: μ≠4.00 Mbps T-Test μ<4.00 t=−2.869485 p=0.003303 x=3.43 Sx=1.256322 n=40 Identify the test statistic.Test the claim that the mean GPA of night students is significantly different than 2.5 at the 0.1 significance level. The null and alternative hypotheses would be: Ho p=0.625 Hop=2.5 Ho: p=0.625 Ho: : H₁: p > 0.625 The test is: right-tailed left-tailed two-tailed о :p = 0.625 Hoμ = 2.5 H₁ μ = 2.5 o H₁:μ> 2.5 H₁: p < 0.625 H₁: p0.625 H₁: μ2.5 H₁: μ< 2.5 Based on a sample of 35 people, the sample mean GPA was 2.47 with a standard deviation of 0.06 The p-value is: -1.645 The positive significance level is: .10 Based on this we: OTT Reject the null hypothesis Fail to reject the null hypothesis X (to 3 decimals) o(to 2 decimals)8.
- ThanksK The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 5.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Click the icon to view the display from technology. D iew an example Get more help. 42 W S Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? OA. Ho: 5.00 Mbps J D. Ho: -5.00 Mbps H₁: - Clear all : - ; X option F11 { [ ? + = 1 I Check answer F12 } ] delete retuPlease help me with this question.
- Imagine that you found that participants in the jelly bean condition had an average acne score o and your significance level was .041. Because your signifinace level is lEss than .05 you reject the null hypothesis. Result #2 imagine that you found that the participants in the jelly bean condition had an average acne score of and your significance level was .00. Because your significance level is less than .05 you reject the null hypothesis. You also note that this result suggest a bigger effect size(30verus10 on your dependant variable). What is the ma in difference between the two scenarios?A data set includes data from student evaluations of courses. The summary statistics are n= 95, x over bar = 3.44, s= 0.64. Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 3.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What is the hypothesis? What is the test statistic? What is the p-value? What is the final conclusion that addresses the original claim? Is there suficient evidence to conclude that the original claim that the mean of the population of student course evaluations is equal to 3.50 is or is not correct?Answer the following to summarize the test of the hypothesis that there is no dependence between the two variables color vision of participant and trial outcome. For your test, use the 0.05 level of significance. a. Find the value of the test statistic. (Round to two or more decimal places.) b. Find the critical value for a test at the 0.05 level of significance. (Round to two or more decimal places.) c. Can we reject the hypothesis that there is no dependence between the variables color vision of participant and trial outcome? Use the 0.05 level of significance.