This gives us 1 M4 = [8 cos(1) 9 + 8 cos 64 Cos(24) + 8 cos(255) + 8 cos(4)] 49 64 64 × (rounded to six decimal places) Therefore, using the Midpoint Rule with n = 4 and rounding to six decimal places we have 1 8 cos(x²) dx≈ Х

Q: sinx = 5/13, x E 5,1], then cosx =?

A: We are solving the problem by the property of trigonometry ratio.

Q: sin(cos¬1/2x²) = v3x? sO:

A: Given:   SinCos-1 2x2=3x2   To find out: x=?

Q: If csc e = 1/3t, then where defined, cos 0 A) Square root of (1 – 9t²) 3t/squareroot of (1 – 9t2)…

A:

Q: Find d coscrin' (-2] the exact value

A: Find the exact value cossin-25.

Q: -3RT/2 b. Smt cos³x sinx dx

A:

Q: 1 dx 6- cos²xsin²x

A: use trigonometric identity to prove the integral

Q: DIFFERENTIATE THE GIVEN y = x² co sec™ 3 -1 * COS

A:

Q: 2 Cos4 Sin (sinz) de

A: Consider the integral  ∫cosxsin2sinxdx

Q: A/ 10 Evaluate 4/1+ cos 10x dx. A/ 10 4/1+ cos 10x dx =

A:

Q: Find dy/dx for 4 cos4 xsiny = 15

A: d(uv)dx=udvdx+dudxv

Q: Find cos(u+v) sinu= -4/5 with 3pi/2 <u<2pi and cosv= -5/13 with pi/2 <v<pi

A: u is in the fourth quadrant. There cos will be positive.

Q: Evaluate COs 2 4 – x² dx

A: use the property of even function and odd function to evaluate the integral.

Q: Find S(-sin³0 – sin@cos20)d0

A: This can be solved as follows:

Q: a. y= 3(x³+4) b. y= cos-1(-3x)

A: we have to find dy/dx for given y

Q: Find   cos(u/2)   if   sec u=7.519

A:

Q: T/4 sin2 x 2. :- cos? dx CoS2 COS x 7/4

A: To find the value of the given integral.

Q: Find S(sin20cose + cos30)d0

A:

Q: Use the identity cos alpha cos beta = 1/2[cos(a-b)+cos(a+b)] to rewrite 2cos3xcos2x as a sum of trig…

A: The given identity

Q: Find a trig substitution r = f(@) that makes 1 dr = cos 0 de. (V4+)3

A: Here we have to substitute x =f(θ)