One approach to evaluating 2 cos (2x)dx is to first rewrite it as cos(4x) + 1 dx а. cos(2x) – 1 dx b. С. cos(4x)+ 1)dx O d. cos(2x) + 1 dæ е. (cos(4x) – 1)dx f. (2 cos(4x) – 1)dx -

Q: te √e³x Evaluate 3x cos 4x dx.

A:

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A:

Q: fip xp COS T 2. Oa) 2x sin(x) cos(2x) P-sin(2x) d- sin(x)+2x Osin(x) acer

A: y=cos (x2) We need to find dydx

Q: 1. Determine (i) |cos (2x– 7) dx dx (ii) x +9 (ii) dx 4-9x² 2. Determine (sin x cos x dx using (1)…

A: Since, you have posted multiple questions we will only first question with three subparts as per our…

Q: ∫sin5(6x)cos(6x)dx

A: ∫xn=xn+1n+1+C

Q: 7T 2 Find 35 cos(7x) dx 5π 2 7T 2 35 35 cos(7x) dx = -5π လ

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Q: Find all solutions Cos(x/2)-cosx = 0

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Q: IV. 4x + 2 dx x² + x + 5 V. 2x – 1 dx x² – 7x + 10 VI. | sin(3x) cos(5x) dr

A:

Q: Evaluate 1₁-² 63 dx 1- cos (9x) 63 dx 1- cos (9x) - 7 cot 9x 2 +C

A: To evaluate the given integral.

Q: Compute | a° sin(æ" + 2) dæ.

A: Given : ∫x6sinx7+2dx

Q: A/ 10 Evaluate 4/1+ cos 10x dx. A/ 10 4/1+ cos 10x dx =

A:

Q: Evaluate | cos5 (9x) sin(9x) da

A: we use the method of substitution to evaluate the given integral.