These two waves travel along the same string: Y, = (3.80 mm) sin(2.45xx - 340xt) Y2 = (6.00 mm) sin(2.45xx - 340xt + 0.868xrad). What are (a) the amplitude and (b) the phase angle (relative to wave 1) of the resultant wave? (c) If a third wave of amplitude 5.12 mm is also to be sent along the string in the same direction as the first two waves, what should be its phase angle in order to maximize the amplitude of the new resultant wave?

These two waves travel along the same string: Y, = (3.80 mm) sin(2.45xx - 340xt) Y2 = (6.00 mm) sin(2.45xx - 340xt + 0.868xrad). What are (a) the amplitude and (b) the phase angle (relative to wave 1) of the resultant wave? (c) If a third wave of amplitude 5.12 mm is also to be sent along the string in the same direction as the first two waves, what should be its phase angle in order to maximize the amplitude of the new resultant wave?

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Question

These two waves travel along the same string:
Y1 = (3.80 mm) sin(2.45xx - 340at)
Y2 = (6.00 mm) sin(2.45xx - 340nt + 0.868arad).
What are (a) the amplitude and (b) the phase angle (relative to wave 1) of the resultant wave? (c) If a third wave of amplitude 5.12 mm is also to be sent along the string in the same direction as the first two waves, what
should be its phase angle in order to maximize the amplitude of the new resultant wave?
(a) Number
Units
(b) Number
Units
(c) Number
Units

Expert Solution

Step 1

Given :

Two waves travel along the same string :

$y_{1} = (3.8 m m) \sin (2.45 π x - 340 π t) y_{2} = (6 m m) \sin (2.45 π x - 340 π t + 0.868 π r a d)$

From the above equations,

Amplitude of wave 1, $y_{m 1} = 3.8 m m$

Phase angle of wave 1, $φ_{1} = 0$

Amplitude of wave 2, $y_{m 2} = 6 m m$

Phase angle of wave 2, $φ_{2} = 0.868 π$

Amplitude of wave 3, $y_{m 3} = 5.12 m m$

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