There's a point charge of q1 = 4.00 nC is at the point x = 0.60 m, y = 0.80 m , and a second point charge q2 = -6.00 nC is at the point x = -0.60 m , y = 0.80m a. Find magnitude of resultant electric field at origin b. Find magnitude of electric field E2 (N/C) at origin due to q2 c. Find magnitude of electric field E1 (N/C) at origin due to of q1
There's a point charge of q1 = 4.00 nC is at the point x = 0.60 m, y = 0.80 m , and a second point charge q2 = -6.00 nC is at the point x = -0.60 m , y = 0.80m a. Find magnitude of resultant electric field at origin b. Find magnitude of electric field E2 (N/C) at origin due to q2 c. Find magnitude of electric field E1 (N/C) at origin due to of q1
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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There's a point charge of q1 = 4.00 nC is at the point x = 0.60 m, y = 0.80 m , and a second point charge q2 = -6.00 nC is at the point x = -0.60 m , y = 0.80m
a. Find magnitude of resultant electric field at origin
b. Find magnitude of electric field E2 (N/C) at origin due to q2
c. Find magnitude of electric field E1 (N/C) at origin due to of q1
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Step 1 :Introduction
VIEWStep 2 :Explanation
VIEWStep 3 :Calculation of the electric field vector due to q1
VIEWStep 4 :Calculation of the electric field vector due to q2
VIEWStep 5 :Calculation of the resultant electric field vector
VIEWStep 6 :Calculation of the magnitude of the resultant field
VIEWStep 7 :Calculation of the magnitude of the electric field E1
VIEWStep 8 :Calculation of the magnitude of the electric field E2
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