Therefore, the roots are, r₁ = 1, r2 = -1. Substitute r 1 in the system. www 1 -1 () ()-() = 3 -3 Then, from the reduced form, the equation obtained is, 1 - 2 = 0 Therefore, the corresponding eigen vector is obtained as, (²) = (1)

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A: Here. We have to find the relationship between eigenvalues and characteristics polynomial.

Q: Hi I need this right now pls, Thank you

A: Eigen value: A=010001512k3-192k224kThe characteristic equation is|A-λI|=0

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A:

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A: NOTE: According to guideline answer of first question can be given, for other please ask in a…

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A:

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A:

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A: Given:          A=2-10-310-6-617-10 To get Eigenvalues    A-λI=0       2-λ-10-310-λ-6-617-10-λ=0

Q: ab. A-1 -1 5 -5 AXI= 사 5 -5 = 저 - 5 -5-7 det(A-xz)=(지(5-2) - (-1)(5) a = 2² +62 +5 +5 = 2² +67+10…

A:

Q: 3. 8. -2 . -3.

A:

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Q: Can step 2 be more elaborated upon? Specifically on how each eigenspace is found.

A:

Q: 4.( )Find the eigenvalue and eigenvector of the matrix: 2 0-2 0 4 0 -2 0

A: If Av=λv for vA=0, we say that λ is the eigenvalue for v, and that v is an eigenvector for λ.

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A: Solution is given below:

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Q: "The eigen values of Hermitian operator are real. What you can say about eigen values"

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Q: 11. Let A -3 = [36]. Find its eigenvalues. 2

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Q: how could i show that the M eigenvalues are equal to the roots computed before (for real repeated)…

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Q: Explain how to determine the dominant eigen value based on the solution above

A: