Answer the exercises in the picture ExerciseThere is an electric potential of 120 V at a point that is 0.25 m away from a charge. Find themagnitude and sign of the charge.Potential at a Point Due to Several ChargesLet us say we have a group of charges arranged as shown in Figure 2.5.Q,Q2Q3Figure 2.5. Potential at a point due to several chargesThe potential at point P due to charges Q1, Q2, and Q3 cab be calculated by getting thepotential due to each of the three charges, V,, V2, and V3. Then, we get the sum of the threepotentials. In equation form, we get:V, = Ev. = kEor,Q3+k-r3Vp = k+ kr2ExerciseFour-point charges are placed at the four corners of a square that is 30 cm on each side. Findthe potential at the center of the square given that each of the four charges has a magnitude of+2 μC.Electric Potential Energy at a Point due to a ChargeIf we have a charge +q at infinity (which is at zero potential) and it is brought to a point P,r distance away from a charge Q, we can find the potential difference AV, to be equal to apotential at P minus the potential at infinity (0). In equation form,QqAPE = k -The work required to bring q from infinity to P is also the PE of the system.ExerciseTwo-point charge of 0.04 µC and 0.16 µC are 20 cm apart in air. (a) What is the potentialenergy of the system? (b) Find the work required to bring two charges to 10 cm from eachother.Electric Potential Energy of Several Charges0.Suppose we have a system of charges Q1, Q2, and Q3(see Figure 2.6). In the diagram, we have three pairs ofcharges: Q,Q2, Q2Q3, and Q1Q3. The total potential energy ofthe system is:Q.Q2EPEtotal = kQ2Q3+ k-Q123+ kr23r13Figure 2.6. A system of charges ExerciseThree-point charges 10 C, -20 C, and -50 C are at the three consecutive corners of asquare 10 cm on a side. What is the total potential energy of the system?The Electron VoltLet us say we have an electron in an electric field between two parallel plates which areoppositely charged. If the electric field between the two plates is directed upward, which meansthat the lower plate is positive and the upper plate is negative, the force it exerts on the negativeelectron is directed downward. To move it from the lower plate to the upper plate, work must bedone on it. An external force directed upward must be exerted to be able to move it from the lowerplate to the upper plate. This suggests that the potential energy of the electron at the upper plateis greater than its potential energy at the lower plate. If the electron is placed at the upper plate,it will accelerate downward thereby decreasing its potential energy. This decrease in potentialenergy means an increase in kinetic energy.ΔΚΕ qVThe charge of an electron is 1.6 x 10-19 C. Therefore, when it moves through a potentialdifference of 1 volt, its kinetic energy increases byAKE = 1.6 x 10-19 C (1 V)= 1.6 x 10-19This is the amount of energy equivalent to one electron volt. In other words, one electron volt isequivalent to 1.6 x 10-19 J of kinetic energy. An electron volt is a unit of energy given as eV. Itis, therefore, convenient to use this unit of energy in dealing with atomic particles.ExerciseLet us say that a proton has a kinetic energy of 4.8 x 10-19J. What is the energy in electronvolts?

Note : Since there is multiple questions, as per guidelines we can only answer to first question.…

Answered: There is an electric potential of 120 V…

There is an electric potential of 120 V at a point that is 0.25 m away from a charge. Find the magnitude and sign of the charge.

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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