5. A cannon fires a projectile perfectly horizontal with initial speed of vi = 40m/s. The cannon Quinontol dictonce R from the launch position will the proiectile hit the ground? For sim
5. A cannon fires a projectile perfectly horizontal with initial speed of vi = 40m/s. The cannon Quinontol dictonce R from the launch position will the proiectile hit the ground? For sim
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter3: Vectors
Section: Chapter Questions
Problem 58PQ: Peter throws a baseball through a houses window. He stands 3.4 m from the window. The ball starts in...
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![**Problem 5: Horizontal Projectile Motion**
*A cannon fires a projectile perfectly horizontal with an initial speed of \( v_i = 40 \, \text{m/s} \). The cannon is at an initial height of \( H = 5 \, \text{m} \). At what horizontal distance \( R \) from the launch position will the projectile hit the ground? For simplicity use \( g = 10 \, \text{m/s}^2 \).*
---
**Solution**
To solve this problem, use the following steps:
1. **Calculate the time of flight:**
Since the projectile is launched horizontally, the time \( t \) it takes to hit the ground depends only on the vertical motion.
\[
H = \frac{1}{2}gt^2
\]
\[
5 = \frac{1}{2}(10)t^2
\]
\[
5 = 5t^2
\]
\[
t^2 = 1 \quad \Rightarrow \quad t = 1 \, \text{second}
\]
2. **Calculate the horizontal distance \( R \):**
The horizontal distance is calculated using the horizontal speed and the time of flight:
\[
R = v_i \times t
\]
\[
R = 40 \, \text{m/s} \times 1 \, \text{s}
\]
\[
R = 40 \, \text{meters}
\]
Therefore, the projectile will hit the ground at a horizontal distance of 40 meters from the launch position.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe6428e04-34b4-4bed-b4b6-b4b3ef1f2aad%2F95f996c4-7d0c-445f-a518-ebb7ccc505f2%2Ff7jumvo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 5: Horizontal Projectile Motion**
*A cannon fires a projectile perfectly horizontal with an initial speed of \( v_i = 40 \, \text{m/s} \). The cannon is at an initial height of \( H = 5 \, \text{m} \). At what horizontal distance \( R \) from the launch position will the projectile hit the ground? For simplicity use \( g = 10 \, \text{m/s}^2 \).*
---
**Solution**
To solve this problem, use the following steps:
1. **Calculate the time of flight:**
Since the projectile is launched horizontally, the time \( t \) it takes to hit the ground depends only on the vertical motion.
\[
H = \frac{1}{2}gt^2
\]
\[
5 = \frac{1}{2}(10)t^2
\]
\[
5 = 5t^2
\]
\[
t^2 = 1 \quad \Rightarrow \quad t = 1 \, \text{second}
\]
2. **Calculate the horizontal distance \( R \):**
The horizontal distance is calculated using the horizontal speed and the time of flight:
\[
R = v_i \times t
\]
\[
R = 40 \, \text{m/s} \times 1 \, \text{s}
\]
\[
R = 40 \, \text{meters}
\]
Therefore, the projectile will hit the ground at a horizontal distance of 40 meters from the launch position.
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